Hey I can help give me one moment .
Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,
m1*m2=-1
So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...
3y=6x ?3 (not sure what you wanted to type there)
anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.
So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:
y=-x/2 +b, we can now you the point given to solve for b
4=-2/2 +b
4=-1+b
b=5 so
y=-x/2 +5 or more neatly
y=(10-x)/2
Step-by-step explanation:
11.68-0.48
= 11.20
11.20÷1.6
= 7.0 or 7
ahh this is the correct answer.
so if it helps don't forget to like and Mark me.
Given:
The equation of a quadratic function is:

To find:
The equation of the axis of symmetry for the given function.
Solution:
If a quadratic function is
, then the equation of the axis of symmetry is:
...(i)
We have,

Here,
. So, the equation of axis of symmetry by using (i), is
Therefore, the correct option is C.
4x+7=-3
4x=-3-7
4x=-10
X=-10/4
X=-2.5