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salantis [7]
3 years ago
13

A certain medicine is given in an amount proportional to a patient's body weight. Suppose a patient weighing 153 pounds requires

249 milligrams of medicine. What is the amount of medicine required by a patient weighing 102 pounds?
Mathematics
2 answers:
mario62 [17]3 years ago
7 0
Mg required per pound = 249/153 = 1.63mg

Therefore medicine required=  102 *1.63= 166.26g

Sonja [21]3 years ago
5 0

Answer: 166 milligrams

Step-by-step explanation:

Given : A certain medicine is given in an amount proportional to a patient's body weight.

A patient weighing 153 pounds requires 249 milligrams of medicine.

Let x be the amount of medicine required by a patient weighing 102 pounds, then we have the following equation:-

\dfrac{x}{102}=\dfrac{249}{153}\\\\\Rightarrow\ x=\dfrac{249\times102}{153}=166

Hence, the amount of medicine required by a patient weighing 102 pounds = 166 milligrams.

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Answer:

y = -3x + 5

Step-by-step explanation:

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Anyone care to help me?
Volgvan
The answer would be x-16=31
8 0
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PLEASE ANSWERRRRRRR! THANKS!!!!!!!!!!!!!!!!!!!!!!<br><br> Solve for x. <br><br> 57 = 3x + 12
Blizzard [7]

57-12= 3x+12-12

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6 0
3 years ago
What is the area of this figure?<br> Enter your answer in the box below.​
viva [34]

Answer:

A = 81 m²

Step-by-step explanation:

The formula for area of the parallelogram is

 A = LH         where L is the length of the base, and H is the height

L is given as 9, and H is given as 5, so

 A = (9)(5) = 45 m²

The are of the triangle is

 A = (1/2)bh         where b is the base and h is the height

b is given as 9.  Its's 9 because that side of the parallelogram is parallel to the base of the parallelogram and is also equal in measure.  The height of the triangle is give as 8, so the area is..

 A = (1/2)(9)(8)

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8 0
3 years ago
A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res
Alexus [3.1K]

Answer:

Step-by-step explanation:

Hello!

So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:

X: "Lifetime of one shoe pair of the new model"

Applying CLT:

X[bar]≈N(μ;σ²/n)

Known values:

n= 30 shoe pairs

x[bar]: 17 months

S= 5.5 months

Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:

H₀:μ=15

H₁:μ≠15

The significance level for the test is given: α: 0.05

Your critical region will be two-tailed:

Z_{\alpha /2} = Z_{0.025}= -1.96

Z_{1-\alpha /2} = Z_{0.975}= 1.96

So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96

Now you calculate your observed Z-value

Z=<u>x[bar]-μ</u> ⇒ Z=<u>    17-15     </u> = 1.99

     σ/√n              5.5/√30

Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.

I hope you have a SUPER day!

5 0
3 years ago
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