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Katarina [22]
2 years ago
14

Oscar recorded the amount of his monthly electric bill for the first 11 months of the year. An ordered list of the amount in dol

lars of his
monthly bills is shown.

79.98, 99, 99, 102, 105, 119, 122, 124, 125, 127

Oscar budgeted $110 per month for his electric bill.

What would be the amount of his last monthly bill in order for the mean bill amount to be $110 for all 12 months?
A $105
B $109
C. $110
D $112
E $121
Mathematics
1 answer:
grandymaker [24]2 years ago
8 0

Answer:

b

Step-by-step explanation:

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6 0
3 years ago
The rate of change of revenue (in dollars per calculator) from the sale of x calculators is R′(x)=(x+1)ln(x+1)R ′ (x)=(x+1)ln(x+
jekas [21]

Answer:

Total revenue = \frac{169}{2}\ln(13)-\frac{169}{4}  dollars

Step-by-step explanation:

R'(x)=(x+1)\ln(x+1)

Integrate with respect to x.

R(x)= ∫(x+1)\ln(x+1) dx

Take x+1=u

Differentiate with respect to x

dx=du

So,

R(x)= ∫u\ln(u)\,du

Use integration by parts: ∫f g dx = f∫ g dx-∫(∫g dx)f' dx

Therefore,

R(x)=  \frac{u^2}{2}\ln(u) -  ∫\frac{u^2}{2}\frac{1}{u}\,du

=  \frac{u^2}{2}\ln(u) -  ∫\frac{u}{2}\,du

Put u=x+1

R(x)=   \frac{(x+1)^2}{2}\ln(x+1)-\frac{(x+1)^2}{4}

To find total revenue from the sale of the first 12 calculators, put x=12

R(x)=   \frac{(12+1)^2}{2}\ln(12+1)-\frac{(12+1)^2}{4}\\\\= \frac{(13)^2}{2}\ln(13)-\frac{(13)^2}{4}\\\\=\frac{169}{2}\ln(13)-\frac{169}{4}

Total revenue = \frac{169}{2}\ln(13)-\frac{169}{4}  dollars

4 0
2 years ago
Which mathematical equation represents the solution for k in the equation h + 3 = jk + 6k ?
Tomtit [17]

Answer:

The answer is<u> D.</u> h+3/j+6.

Step-by-step explanation:

Given:

The equation h + 3 = jk + 6k.

Now, to get the mathematical expression.

h + 3 = jk + 6k

So, taking k common on R.H.S we get:

h + 3 = k(j + 6)

Then, dividing both sides by j+6  we get:

\frac{h+3}{j+6} =k

Thus,

k=\frac{h+3}{j+6}

Therefore, the answer is D. h+3/j+6.

5 0
3 years ago
A population of 1,750 cheetahs decreases by 10% per year. How many cheetahs will there be in the population after 11 years? Roun
Triss [41]

Answer:

The answer is C. 546.

If a population decreases by 11%, that means that 89% (100% - 11% = 89%) of cheetahs remains each number. 89% can be expressed as 0.89, so to calculate the change of the population, we must each year multiply the number of cheetahs by 0.89.

After 1 year:     1750 * 0.89 ≈ 1558

After 2 years:  1558 * 0.89 ≈ 1387

After 3 years:  1387 * 0.89 ≈ 1234

After 4 years:  1234 * 0.89 ≈ 1098

After 5 years:  1098 * 0.89 ≈ 977

After 6 years:  977 * 0.89 ≈ 870

After 7 years:  870 * 0.89 ≈ 774

After 8 years:  774 * 0.89 ≈ 689

After 9 years:  689 * 0.89 ≈ 613

After 10 years:  613 * 0.89 ≈ 546

Step-by-step explanation:

4 0
2 years ago
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