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Harlamova29_29 [7]
3 years ago
13

Which statement is true about the given info

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0

Answer:

AEC es 90

Step-by-step explanation:

you're already correct

Anettt [7]3 years ago
6 0

Answer: the one you have selected is correct.

ACE = 90

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What is the sum of the measures of the interior angles of a pentagon and 10-gon (decagon)?
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Answer:

540

Step-by-step explanation:

sum of interior angles =(n-4)90

(10-4)90=

6×90=540

5 0
3 years ago
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1111111 is the answer

Step-by-step explanation:

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3 years ago
Michael earns 7 for each lawn he mows he wants to earn at least 45 write an inequality to show how many laws michael could mow s
Sidana [21]

Answer:

At least means... From 45$ above or It should be equal to 45 or More...

7x≥45

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3 years ago
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AlladinOne [14]
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7 0
3 years ago
A certain restaurant always overbooks. If possible. At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53
oee [108]

Answer:

The probability that the restaurant can accommodate all the customers who do show up is 0.3564.

Step-by-step explanation:

The information provided are:

  • At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
  • If the probability of a party not showing up is 0.04.
  • Assuming independence.

Let <em>X</em> denote the number of parties that showed up.

The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.

As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.

Compute the probability that the restaurant can accommodate all the customers who do show up as follows:

P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564

Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.

7 0
3 years ago
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