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Ket [755]
4 years ago
14

What is the center of the circle with the equation (x+4)^2 + (y - 2)^2 = 16? a (-4, -2) b (4,2) c (-4, 2) d (4, -2)

Mathematics
2 answers:
Lina20 [59]4 years ago
5 0

Answer:

The center is ( -4,2) and the radius is 4

Step-by-step explanation:

The equation of a circle can be written as

( x-h) ^2 + ( y-k) ^2 = r^2 where ( h,k) is the center and r is the radius

(x+4)^2 + (y - 2)^2 = 16

(x- -4)^2 + (y - 2)^2 = 4^2

The center is ( -4,2) and the radius is 4

mrs_skeptik [129]4 years ago
3 0

Answer:

C) (-4, 2)

Step-by-step explanation:

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The equation represents an ellipse. which point is the center of the ellipse? (−9, 5) (−5, 9) (5, −9) (9, −5)
Igoryamba

The point which is the center of the ellipse whose equation is; (y+5)²/121+(x-9)²/49=1 s in the task content is; (-5, 9).

<h3>Which point represents the center of the ellipse whose equation is given as; (y+5)²/121+(x-9)²/49=1?</h3>

It follows from convention that the equation of an ellipse usually takes the form;

(y-h)²/a²+(x-k)²/b²=1 in which case, the center of the ellipse is given by the point; (h, k).

On this note, By comparison of the actual equation and the standard equation, it follows that;

+5 = -h and consequently, h = -5,

-9 = -k and consequently, k = 9.

Ultimately, the point which is the center of the

ellipse is; (-5, 9).

Remark: The equation of the ellipse which is missing in the task content is; (y+5)²/121+(x-9)²/49=1

Read more on center of an ellipse;

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