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Ket [755]
3 years ago
14

What is the center of the circle with the equation (x+4)^2 + (y - 2)^2 = 16? a (-4, -2) b (4,2) c (-4, 2) d (4, -2)

Mathematics
2 answers:
Lina20 [59]3 years ago
5 0

Answer:

The center is ( -4,2) and the radius is 4

Step-by-step explanation:

The equation of a circle can be written as

( x-h) ^2 + ( y-k) ^2 = r^2 where ( h,k) is the center and r is the radius

(x+4)^2 + (y - 2)^2 = 16

(x- -4)^2 + (y - 2)^2 = 4^2

The center is ( -4,2) and the radius is 4

mrs_skeptik [129]3 years ago
3 0

Answer:

C) (-4, 2)

Step-by-step explanation:

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Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10.  Each time we have a new term, the next one is the same except that 10 is added.

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June starts a savings account and puts $1,500 in it. She ears a compound interest of 3% in 3 years. How much is the balance?
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