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3 years ago

Select all angles that MUST be supplementary to 9

Mathematics

1 answer:

erastova [34]3 years ago

6 0

Answer:

Angles supplementary to angle 9 = Angle 10, 7, 5, 1, 4, 3, 15, 12, 24, 22, 20, 19, and angle 16.

Step-by-step explanation:

Use the vertical, and corresponding angles theorem to find congruent angles.

Look for linear pairs (adjacent(next to each other, or share a side) angles that make 180° or a straight angle) from the corresponding angles.

Something is supplementary if it adds to 180 degrees.

The vertical angles theorem states that pairs of opposite angles made by interesecting lines are congruent.

The corresponding angles theorem states that corresponding or angles relative to the same position are congruent if the transversal crosses at least 2 parallel lines.

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Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!

blagie [28]

Question 4

1) $\overline{BD}$ bisects $\angle ABC$ , $\overline{EF} \perp \overline{AB}$ , and $\overline{EG} \perp \overline{BC}$ (given)

2) $\angle FBE \cong \angle GBE$ (an angle bisector splits an angle into two congruent parts)

3) $\angle BFE$ and $\angle BGE$ are right angles (perpendicular lines form right angles)

4) $\triangle BFE$ and $\triangle BGE$ are right triangles (a triangle with a right angle is a right triangle)

5) $\overline{BE} \cong \overline{BE}$ (reflexive property)

6) $\triangle BFE \cong \triangle BGE$ (HA)

Question 5

1) $\angle AXO$ and $\angle BYO$ are right angles, $\angle A \cong \angle B$ , $O$ is the midpoint of $\overline{AB}$ (given)

2) $\triangle AXO$ and $\triangle BYO$ are right triangles (a triangle with a right angle is a right triangle)

3) $\overline{AO} \cong \overline{OB}$ (a midpoint splits a segment into two congruent parts)

4) $\triangle AXO \cong \triangle BYO$ (HA)

5) $\overline{OX} \cong \overline{OY}$ (CPCTC)

Question 6

1) $\angle B$ and $\angle D$ are right angles, $\overline{AC}$ bisects $\angle BAD$ (given)

2) $\overline{AC} \cong \overline{AC}$ (reflexive property)

3) $\angle BAC \cong \angle CAD$ (an angle bisector splits an angle into two congruent parts)

4) $\triangle BAC$ and $\triangle CAD$ are right triangles (a triangle with a right angle is a right triangle)

5) $\triangle BAC \cong \triangle DCA$ (HA)

6) $\angle BCA \cong \angle DCA$ (CPCTC)

7) $\overline{CA}$ bisects $\angle ACD$ (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) $\angle B$ and $\angle C$ are right angles, $\angle 4 \cong \angle 1$ (given)

2) $\triangle BAD$ and $\triangle CAD$ are right triangles (definition of a right triangle)

3) $\angle 1 \cong \angle 3$ (vertical angles are congruent)

4) $\angle 4 \cong \angle 3$ (transitive property of congruence)

5) $\overline{AD} \cong \overline{AD}$ (reflexive property)

6) $\therefore \triangle BAD \cong \triangle CAD$ (HA theorem)

7) $\angle BDA \cong \angle CDA$ (CPCTC)

8) $\therefore \vec{DA}$ bisects $\angle BDC$ (definition of bisector of an angle)

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2 years ago

A -pound bag of Feline Flavor is . An -pound bag of Kitty Kibbles is . Which statement about the unit prices is true?

ser-zykov [4K]

Answer:

Where is the numbers dude? LOL

Step-by-step explanation:

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2 years ago

Find the LCM of the following. A. 28,42,35 B. 48,72,96 C. 36, 44

Ne4ueva [31]

28/2= 14 42/2= 21 35/7= 5

14/ 2= 7 21/3= 7

28= 2^2 × 7

42= 2 × 3 × 7

35= 7 × 5

LCM= 420

48/2= 24. 72/2= 36. 96/3= 32

24/2= 12. 36/3= 12. 32/2= 16

12/3= 4. 12/3= 4. 16/2= 8

4/2= 2. 4/2= 2. 8/2= 4

4/2= 2

48= 2^4 × 3

72= 2^3 × 3^2

96= 2^5 × 3

LCM= 288

36/3= 12. 44/2= 22

12/3= 4. 22/2= 11

4/2= 2

36= 3^2 × 2^2

44= 2^2 × 11

LCM= 396

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2 years ago

Read 2 more answers

In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to

Anvisha [2.4K]

Answer:

5 + 3p ≥ 30

Step-by-step explanation:

"at least" means greater than are equal to. ≥

So we already know he has 5 points, but the other 3 rounds we don't. 5 + 3p

30 is the overall points he has.

5 + 3p ≥ 30

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3 years ago

19) *

RUDIKE [14]

The correct answer is 18 sides.

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3 years ago