<span>10<span>(<span><span>122<span>(13)</span></span><span>(12)</span></span>)</span></span><span>=<span><span>10<span>(122)</span></span><span>(156)</span></span></span><span>=<span><span>(10)</span><span>(19032)</span></span></span><span>=<span>190320
Hope You understand
This is just basic multiplication.</span></span>
Answer:
I think [(-4)^4]^5, but I'm not completely sure
Step-by-step explanation:
1.0995116e+12 greater than -4.7223665e+21
[(-4)^4]^5=1.0995116e+12
-[(4^12)^3=-4.7223665e+21
Answer:
neither
Step-by-step explanation:
parallel run side by side and perpendicular cross at 90 degree angle. these equations come out to looking like a X
Answer:
Step-by-step explanation:
By putting the numbers in the given equation,
2x + 3 + 3x = 7x + 9
5x + 3 = 7x + 9
(5x + 3) - 7x = (7x + 9) - 7x
(5x - 7x) + 3 = 9
-2x + 3 = 9
(-2x + 3) - 3 = 9 - 3
-2x = 6
-x = 3
x = -3
Therefore, our equation is correct which has a negative result.
In place of 6 if we use 8, value of x will be negative again.
Answer:
29.2
Step-by-step explanation:
Mean = 21.4
Standard deviation = 5.9%
The minimum score required for the scholarship which is the scores of the top 9% is calculated using the Z - Score Formula.
The Z- score formula is given as:
z = x - μ /σ
Z score ( z) is determined by checking the z score percentile of the normal distribution
In the question we are told that it is the students who scores are in the top 9%
The top 9% is determined by finding the z score of the 91st percentile on the normal distribution
z score of the 91st percentile = 1.341
Using the formula
z = x - μ /σ
Where
z = z score of the 91st percentile = 1.341
μ = mean = 21.4
σ = Standard deviation = 5.9
1.341= x - 21.4 / 5.9
Cross multiply
1.341 × 5.9 = x - 21.4
7.7526 = x -21.4
x = 7.7526 + 21.4
x = 29.1526
The 91st percentile is at the score of 29.1526.
We were asked in the question to round up to the nearest tenth.
Approximately, = 29.2
The minimum score required for the scholarship to the nearest tenth is 29.2 .
