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Luba_88 [7]
3 years ago
11

1. Find the number of distinguishable permutations of the given letters AAABBBCD''.

Mathematics
1 answer:
hoa [83]3 years ago
6 0

Answer:

1. 1120

2, 0.1071

Step-by-step explanation:

1.the number of distinguishable permutations of the given letters

AAABBBCD    A is repeated 3, B is also repeated thrice

= \frac{8!}{3!3!}

=1120

2.If  it begins with at least 2 A's , no. of permutations

\frac{6!}{3!}

=120

Therefore, the probability of random permutations of AA

=120/1120= 3/28= 0.1071

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8 0
3 years ago
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Nutka1998 [239]

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There's a faster way to do this - notice that you need to move the decimal 14 to the right, and there's one number already after the decimal place. Therefore, 13 places will be filled with zeros. So, just write out 63 and add 13 zeros.

For more general help on scientific notation, check out these videos: https://www.khanacademy.org/math/pre-algebra/pre-algebra-exponents-radicals/pre-algebra-scientific-notation/v/scientific-notation-old

Hope that helps! Feel free to message me or leave a comment if I can clarify anything :)

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