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Luba_88 [7]
4 years ago
11

1. Find the number of distinguishable permutations of the given letters AAABBBCD''.

Mathematics
1 answer:
hoa [83]4 years ago
6 0

Answer:

1. 1120

2, 0.1071

Step-by-step explanation:

1.the number of distinguishable permutations of the given letters

AAABBBCD    A is repeated 3, B is also repeated thrice

= \frac{8!}{3!3!}

=1120

2.If  it begins with at least 2 A's , no. of permutations

\frac{6!}{3!}

=120

Therefore, the probability of random permutations of AA

=120/1120= 3/28= 0.1071

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