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pshichka [43]
3 years ago
15

If

middle" class="latex-formula"> and B= log_{5} 3, write each logarithm in terms of A and B.
log_{5} 36
Mathematics
1 answer:
Zolol [24]3 years ago
4 0

Answer:

2A+2B

Step-by-step explanation:

log_{5} 36=log_{5}(4*9)=log_{5}(2^{2}*3^{2})\\log_{5}(2^{2})+log_{5}(3^{2})=2log_{5}2+2log_{5}3=2A+2B

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Round to the nearest hundredth?<br><br>A<br><br>4<br><br>?<br><br>35°<br><br>с<br><br>B
DaniilM [7]

The length of the unknown side length, |AB|, is 6.97

<h3>Trigonometry</h3>

From the question, we are to determine the value of the unknown side length

The unknown side length is the hypotenuse

Using SOH CAH TOA

We can write that

sin 35° = 4/|AB|

∴ |AB| = 4 /sin35°

|AB| = 4 /sin35°

|AB| = 6.97

Hence, the length of the unknown side length, |AB|, is 6.97

Learn more on Trigonometry here: brainly.com/question/22099203

#SPJ1

3 0
1 year ago
Help me with this please
m_a_m_a [10]
36 is the value
answer
4 0
2 years ago
Please help<br><br> (Attachment below)
igor_vitrenko [27]
 the length of  the red line is 12
8 0
3 years ago
Find 5 solutions to the question.<br><br> Y=-1.5x+2
Black_prince [1.1K]

Answer:

<em>☆</em><em><</em><em> </em><em><u>《</u></em><em><u>HOPE IT WILL HELP YOU</u></em><em>》</em><em>></em><em>☆</em>

Step-by-step explanation:

Y=1.5x+2

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>)</u></em></h3>

y=1.5 (1) +2

y=1.5+2

y=3.5

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>2</u></em><em><u>)</u></em></h3>

y=1.5(2)+2

y=3+2

y=5

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>3</u></em><em><u>)</u></em></h3>

y=1.5 (3)+2

y=4.5+2

y=6.5

<h3>(x=4)</h3>

y=1.5 (4)+2

y=6+2

y=8

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em></h3>

y=1.5 (5)+2

y=7.5+2

y=9.5

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3 0
3 years ago
There are four white socks and six black socks in a drawer. What is the probability of selecting a white sock, not replacing it,
m_a_m_a [10]

Answer:

A: 1/3

Step-by-step explanation:

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2 years ago
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