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2 years ago

6(8-3)+3(7-4) evaluat the expression

Mathematics

2 answers:

Ksju [112]2 years ago

7 0

Answer: 39

Step-by-step explanation:

6(8-3)+3(7-4) 1. Make sure to multiply what's in the parentheses first.

6(5)+3(3) 2. Multiply before you add the coefficients

30+9 3. Add

Answer is 39

Tems11 [23]2 years ago

6 0

You do it like this
30+9
39

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Craign has a building block in the shape of a rectangular pyramid .A net of which is shown below.If a measures 12 cm b measures

svetoff [14.1K]

Answer:

<h3>Option D) 294 sq cm is correct</h3><h3>∴ the surface area of the rectangular pyramid is 294 sq cm</h3>

Step-by-step explanation:

First we have to split the net into 4 triangles and 1 rectangle

Given a = 12 cm ,b = 6 cm and d = 13 cm

<h3>To find the surface area of the rectangular pyramid:</h3>

Now find the area of the rectangle base

$Rectangle base area=b\times a$

$= 6\times 12$

= 72 sq. cm

<h3>∴ Rectangle base area=72 sq cm</h3>

Now to find the area of the triangle on the left

$Left triangle=\frac{1}{2}(b)(d)$

$=\frac{1}{2}(6)(13)$

= 39 sq cm

<h3>∴ Left triangle=39 sq cm</h3>

Since all the triangles are congruent , you will need to multiply by 2 to get the combined area of the triangle on the left and on the right.

Area of left and right triangles= 2(39)

=78 sq cm

<h3>∴ Area of left and right triangles=78 sq cm</h3>

Find the area of the triangle on the bottom

$Bottom triangle area=\frac{1}{2}(a)(a)$

$=\frac{1}{2}(12)(12)$

= 72 sq cm

<h3>∴ Bottom triangle area=72 sq cm</h3>

Since the bottom of the triangle is congruent to the top triangle, multiply that by 2 to get a combined area of the triangle on the bottom and top

Area of top & bottom triangles=2 (72)

= 144 sq cm

<h3>∴ Area of top & bottom triangles= 144 sq cm</h3>

Finally add the area of the 4 triangles to the area of the rectangular base we get

=72 + 78 + 144

= 294 sq cm

<h3>∴ the surface area of the rectangular pyramid is 294 sq cm</h3><h3>∴ option D) 294 sq cm is correct.</h3>

7 0

3 years ago

Can y’all help me with this plzzzz

Leviafan [203]

Answer:

the answer is 1080 so yea

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2

saul85 [17]

$\large\underline{\sf{Solution-}}$

<u>Let us assume that:</u>

$\sf \longmapsto x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ... \infty } } }$

We can also write it as:

$\sf \longmapsto x = \sqrt{6 + x }$

Squaring both sides, we get:

$\sf \longmapsto {x}^{2} =6 + x$

$\sf \longmapsto {x}^{2} - x - 6 =0$

By splitting the middle term:

$\sf \longmapsto {x}^{2} - 3x + 2x - 6 =0$

$\sf \longmapsto x(x - 3) + 2(x - 3 ) =0$

$\sf \longmapsto (x+ 2)(x - 3 ) =0$

<u>Therefore:</u>

$\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}$

$\sf \longmapsto x = - 2,3$

<u>But x cannot be negative. </u>

$\sf \longmapsto x = 3$

Therefore, the value of the expression is 3.

$\large\underline{\sf{Verification-}}$

Given:

$\sf\longmapsto x=3$

We can also write it as:

$\sf\longmapsto x = \sqrt{9}$

$\sf\longmapsto x = \sqrt{6+3}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{9}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}$

This pattern will continue.

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}$

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2 years ago

If AC = 28 meters and BC = 21 meters, what is the measure of angle C?*

mixer [17]

First one answer A/ B B

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2 years ago

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