1 question need help thank you!!

Mathematics

1 answer:

inn [45]3 years ago

7 0

The correct answer is: [D]: " x² – 5x – 24 " .
____________________________________________________
Explanation:
_____________________________________
Given: " (x + 3)(x – 8) " ; expand :
______________________________________
Note: (a + b) (c + d) = ac + ad + bc + bd .
_____________________________________
a = x ;

b = 3 ;

c = x

d = 8
_______________________________________

" (x + 3)(x – 8) " ;

= (x * x) + ( -8 * x) + ( 3 * x ) + (3 * -8) ;

= x² + (-8x) + 3x + (-24) ;

= x² – 8x + 3x – 24 ;

→ Combine the "like terms" :

– 8x + 3x = – 5x ;

And simplify the expression;

to get:

→ " x² – 5x – 24 " ; which is: Answer choice: [D]: " x² – 5x – 24 " .
________________________________________________________

You might be interested in

Use the drawing tools to form the correct answers on the graph. Draw the lines representing the vertical and horizontal asymptot

-BARSIC- [3]

Answer:

vertical asymptote X=-1

horizontal asymptote Y=2

Step-by-step explanation:

7 0

3 years ago

Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

4 0

2 years ago

Last Question plz<br> Need help

patriot [66]

Answer:

Im going to answer your question in the next note.

5 0

3 years ago

Clare is painting some doors that are all the same size. She used 2 liters of paint to cover 1 3/5 doors. How many liters of pai

barxatty [35]

Answer:

$1\frac{1}{4}\ liters$