I’m pretty sure the answer is that last one where t is less than or equal to -12
Answer:
none
Step-by-step explanation:
(2x+3)(4x^2-5x+6)
factor over
8x^3-10x^2+12x+12x^2-15x+18
combine like terms
8x^3 + 2x^2 - 3x + 18
In the rachel problem when a top part of the fraction meets the the same number as the bottom it will become a whole number and it does that 2 times so your awnser should just be 2 wholes. jhons problem is also 3 wholes becausw the top number is the same as the bottom 3 times
Set each factor equal to zero and solve to find the zeros
