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timurjin [86]
3 years ago
11

A right triangle ABC with height AB labeled 3 units and base BC labeled 5 units is shown. The area of the triangle above will eq

ual one half of a rectangle that is 5 units long and units wide.
Mathematics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

Step-by-step explanation:

Answer:

w=3

Step-by-step explanation:

The area of the triangle is given by

A = 1/2 bh

the base is 5 and the height is 3

A = 1/2 (3) * 5 = 15/2  units ^2

The area of a rectangle is

A = l*w

A = 5w

The area of the triangle = 1/2 the area of the rectangle

15/2 = 1/2 *5w

15/2 = 5/2 w

Multiply each side by 2/5 to isolate w

2/5 * 15/2 = 2/5 *5/2 w

3 =w

Read more on Brainly.com - brainly.com/question/11938580#readmore

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A square is changed into a pentagon by building an equilateral triangle on top of it, as shown. By what percent does the perimet
Stella [2.4K]

Answer: The perimeter is going to increase 25% from the square to the pentagon.

Step-by-step explanation:

  • A square is a quadrilateral having its all sides equal.
  • A equilateral triangle is a triangle that has equal sides.

Let the side of the given square be x.

Perimeter of square =4x

If a square is changed into a pentagon by building an equilateral triangle on top of it , Then the base of equilateral triangle will occupy the same side-length as that of square.

Thus , the pentagon will become a regular pentagon having all its sides equal.

Perimeter of pentagon = 5(side)= 5x

Increase in perimeter = Perimeter of pentagon- Perimeter of square

= 5x-4x= x

Now , the percent increase in perimeter = \dfrac{\text{Increase in perimeter}}{\text{Perimeter of square}}\times100

=\dfrac{x}{4x}\times100\\\\ =\dfrac{100}{4}=25\%

Hence, the perimeter is going to increase 25% from the square to the pentagon.

8 0
4 years ago
Answer in factored form x^2+11x+7
KATRIN_1 [288]
X² <span>+ 11x + 7

because 7 is a prime number, this doesn't factor prettily. you'll want to use the quadratic formula; if you aren't familiar with it, i'd either research it or look it up in your textbook, because it's clunky and not easily understood in this format:

(-b </span>± √((b)² - 4ac))/(2a)

in your equation x² + 11x + 7 ... a = 1, b = 11, and c = 7. what you do is you take the coefficients of every term, then plug it into your equation:
(-11 ± √((11)² - 4(1)(7))/(2(1))

not pretty, i know. but, regardless, you can simplify it:
(-11 ± √((11)² - 4(1)(7))/(2(1))
(-11 ± √(121 - 28))/2
(-11 ± √93)/2

and you can't simplify it further. -11 isn't divisible by 2, and 93 doesn't have a perfect square that you can take out from beneath the radical. the ± plus/minus symbol indicates that you have 2 answers, so you can write them out separately:

(x - (-11 - √93)/2) and (x + (-11 - √93)/2)

they look confusing, but those are your two factors. they can be simplified just slightly by changing the signs in the middle due to the -11:

(x + (11 + √93)/2) (x - (11 - √93)/2)

and how these would read, just in case the formatting is too confusing for you: x plus the fraction 11 + root 93 divided by 2. the 11s and root 93s are your numerator, 2s are your denominator.
7 0
3 years ago
Solve, using the substitution method. X + y = -11
sladkih [1.3K]

Answer:

A. (-6,-5)

Step-by-step explanation:

A: Correct because -6+-5=-11------True

    and 2(-6)-3(-5) is equal to -12-(-15) and a - plus a - equals a +

    so our new equation is -12+15=3-----True

  -Your welcome and I hope this helps you, please rate 5 stars =D

3 0
3 years ago
Which is the equation of a hyperbola with directrices at x = ±3 and foci at (4, 0) and (−4, 0)?​
Alex Ar [27]

Answer:

\frac{x^2}{12}-\frac{y^2}{4}=1

Step-by-step explanation:

Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:

<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>

  • <u />\frac{x^2}{a^2}-\frac{y^2}{b^2}=1
  • Directrices -> x=\pm\frac{a^2}{c}
  • Foci -> (\pm c,0) where a^2+b^2=c^2
  • a>b

Since we are given our directrices of x=\pm3 and foci of (\pm4,0), then we can set up the directrices equation to solve for a^2:

x=\pm\frac{a^2}{c}\\ \\\pm3=\pm\frac{a^2}{4}\\ \\12=a^2

Now we can determine b^2 to complete our equation for the hyperbola:

a^2+b^2=c^2\\\\12+b^2=4^2\\\\12+b^2=16\\\\b^2=4

Therefore, our equation for our hyperbola is \frac{x^2}{12}-\frac{y^2}{4}=1

5 0
2 years ago
The hypotenuse is NOT located across from the right angle<br><br> True or false
azamat

The statement, The hypotenuse is NOT located across from the right angle is false.

<h3>What is a right angled triangle? </h3>

A right-angled triangle is a type of triangle that has an angle that measures 90 degrees. The triangle has three sides. The hypotenuse is the longest side of a right-angled triangle. Other sides are the base and the length. The sum of sides in a a right-angled triangle is 180 degrees.

Please find attached an image of a right-angled triangle. To learn more about  a triangle, please check: brainly.com/question/9329354

6 0
3 years ago
Read 2 more answers
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