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yawa3891 [41]
3 years ago
10

a child who is 5 ft tall is standing 10 feet from the base of a tree. the child’s shadow has a length of 3 feet. how tall is the

tree ?
Mathematics
2 answers:
Viktor [21]3 years ago
7 0
24 ft tallll i think i didnt double check
Scrat [10]3 years ago
7 0
The answer would most certainly be 5.5ft your welcome
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Workers inc. just bought 14 boxes of pens to put in their storage room for employees to use as needed. each box contains 50 pens
slega [8]

Answer:

568 pens.

Step-by-step explanation:

Total number of pens bought = 14 * 50 = 700.

Total pens taken by the workers = 33 * 4 = 132.

Number left = 700 - 132 = 568.

4 0
4 years ago
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HELP ASAP!! what is the measure of angle h?
SOVA2 [1]
Answer: B
Because they’re congruent angles
3 0
3 years ago
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Part one: Sequence and Series
ASHA 777 [7]

Answer:

- 57

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

Here a = 13 and d = - 2.5, thus

a_{29} = 13 + (28 × - 2.5) = 13 - 70 = - 57

8 0
3 years ago
A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.
creativ13 [48]

Answer:

About 20%

Step-by-step explanation:

The probability of a point on the un-shaded region will be given by;

Area of the shaded region/total area

Considering that the circles are of the same size, then the length of the square is 2d

Area of the square = 4d²

Area of the shaded = (4d² -4π(d/2)²

                                = 4d² -πd², but π = 22/7

                                = 6/7d²

Probability = (6/7d² ÷ 4d²) × 100%

                  = (6/28 d²) × 100%

                  = 21.42 %

Therefore; the answer is about 20%

3 0
3 years ago
Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d​
gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

Step-by-step explanation:

Evaluate:

\dfrac{b-3a}{bc^{2}-d}

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\

\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

6 0
3 years ago
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