Answer: 0.0228
Step-by-step explanation:
Given : The mean and the standard deviation of finish times (in minutes) for this event are respectively as :-
If the distribution of finish times is approximately bell-shaped and symmetric, then it must be normally distributed.
Let X be the random variable that represents the finish times for this event.
z score : 
Now, the probability of runners who finish in under 19 minutes by using standard normal distribution table :-
Hence, the approximate proportion of runners who finish in under 19 minutes = 0.0228
O.6 easy because of the answer that is why
there isnt much here but answer is width=X and length=Y and X times Y
for example, if you had a room that was 3 feet long and 10 feet wide, it would be 30 square feet.
Answer:
(x-9) (x-3)
Step-by-step explanation:
hope this helps:))
Answer:
Z=11.0
Step-by-step explanation:
Let Caucasian individuals be the population 1 and African American be the population 2. So, we are given that
n=150
n1=75
mean1=xbar1=6.1.
standard deviation1=S.D1=σ1=1.1.
Variance1=V(x1)=σ1²=1.1²=1.21.
n2=75.
mean2=xbar2=4.3.
standard deviation2=S.D2=σ2=0.9.
Variance2=V(x2)=σ2²=0.9²=0.81.
The z-statistic is
Z=10.97
Z=11.0
So, the z value obtained while calculating the test statistic is approximately 11.0.
