The figure shows ∆ABC with m∠ABC = 90°.
2 answers:
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Answer:
Pauline reflected the original figure over the x-axis:
The coordinates of point B will be (4,3)
Carl reflected the original figure over the y-axis:
The coordinate of points B will be (-4,-3)
Most quadratic functions(which is what you have there, to a degree of 2) are solved using factoring and the zero product law. If you can not factor then you have to use the quadratic formula or graph it. However this one can be factored.
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,
Then you set each factor to 0 and solve for x,
And the second one,
The solutions to this equation are
x = -1/2, 3
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,
Then you set each factor to 0 and solve for x,
And the second one,
The solutions to this equation are
x = -1/2, 3