3 years ago

The figure shows ∆ABC with m∠ABC = 90°.

Mathematics

2 answers:

notsponge [240]3 years ago

4 0

Answer:

Hello,

Please, see the attached file.

Thanks.

Step-by-step explanation:

emmasim [6.3K]3 years ago

4 0

Answer: the other person is correct

Step-by-step explanation:

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3 years ago

Find the vertex and axis of symmetry for f(x)=2x^2-1

vfiekz [6]

<h3>Axis of symmetry is 0 and vertex is (0, -1)</h3>

Solution:

Given is:

$f(x) = 2x^2 - 1$

We have to find the vertex and axis of symmetry

The general equation is given as:

$f(x) = ax^2 + bx + c$

Comparing with given equation,

a = 2

b = 0

c = -1

The axis of symmetry is given as:

$x = \frac{-b}{2a}$

$x = \frac{0}{2(2)}\\\\x = 0$

Thus axis of symmetry is 0

The x coordinate of the vertex is the same

x coordinate of the vertex = 0

h = 0

The y coordinate of the vertex is:

k = f(h)

k = f(0)

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Thus, y coordinate of the vertex is -1

Therefore, vertex is (0, -1)

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3 years ago