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kramer
3 years ago
8

What is the greatest common factor of theses variables

Mathematics
1 answer:
DerKrebs [107]3 years ago
8 0
B is the answer!

Explanation:
m^2 n^2 fits into both, you can take m^2 n^2 out of it both.

m is a common factor since you can take m out of both but it’s not the greatest common factor.

2n & 2m wouldn’t even be a common factor bc there is no 2n or 2m in neither.
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20 divided by X is 100, what does X equal?
ahrayia [7]
20/ X= 100
⇒ X= 20/100 (inverse operation)
⇒ X= 1/5

Final answer: X= 1/5
7 0
3 years ago
Which of the following functions represents an exponential decay with a 15% rate of change where A represents the initial value
melisa1 [442]

The function that represent this exponential decay is given as y = A(0.85)ˣ

<h3>What is an exponential function?</h3>

An exponential function is in the form:

y = abˣ

Where a is the initial value and b is the multiplication factor.

Given that A is the initial value, there is a decay of 15%, hence:

b = 100% - 15% = 0.85

The function that represent this exponential decay is given as y = A(0.85)ˣ

Find out more on exponential function at: brainly.com/question/12940982

3 0
2 years ago
Riddle
erma4kov [3.2K]

Answer:

100 minutes?

lol

5 0
3 years ago
Read 2 more answers
I need the answer I will mark u brainalist
pashok25 [27]

Answer:

x= 1

Step-by-step explanation:

x = 1 is the axis of symmetric for the graph

if we draw a line parallel to the y axis one units to the right side of the origin we get the line of symmetry of the graph.

and since the line of symmetry is parallel to y axis and passes thru the point (1, 0) it's equation is x= 1

3 0
3 years ago
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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