Question

At which root does the graph of f(x) = (x + 4) 6(x + 7)5 cross the x-axis? 0 -7 ООО

Answer 1

the root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0 is $x = -7$  .

Step-by-step explanation:

We have , f(x) = (x + 4) 6(x + 7)5 i.e.$f(x) = (x+4)^{6}(x+7)^{5}$. We need to find root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0. Let's solve this:

⇒ $f(x) = (x+4)^{6}(x+7)^{5}$

⇒ $0 = (x+4)^{6}(x+7)^{5}$

⇒ $(x+4)^{6}(x+7)^{5} = 0$

Which means either $x+4 = 0\\x = -4$ or , $x+7=0\\x=-7$ . That means the root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0 is $x= -4$ or $x = -7$ . ∴ From given options , the root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0 is $x = -7$  .