At the pet owner’s meeting, there are 20 people who own dog, and 35people who own cat and 9 people own goldfish. Some people own
both catand dog and some people own both gold fish and cat. No dog owners owngoldfish. There are twice as many people who own both goldfish and catthan people who own both dog and cat. Suppose a total of 52 people areat the meeting. Use C for the set of cat owners, D for the set of dog ownersand G for the set of goldfish owners. Answer the following questions andshow your work.How many people own both cat and dog?
1 answer:
Answer:
4
Step-by-step explanation:
Given that At the pet owner’s meeting, there are 20 people who own dog, and 35people who own cat and 9 people own goldfish. Some people own both catand dog and some people own both gold fish and cat. No dog owners owngoldfish. There are twice as many people who own both goldfish and catthan people who own both dog and cat.
Total no of people =52
The venn diagram attached gives a clear picture
assuming x to be owners of both dog and cat. Then 2x is for both goldfish and cats.
Totalling all mutually exclusive we get
64-3x=52
x=4
No of owners who own both cat and dog =4
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Answer:
The constant in the algebraic expression to represent the pattern below is 4.
Step-by-step explanation:
Imortant Tip:
- An Arithmetic sequence has a constant difference 'd' which can be determined by computing the differences of all the adjacent terms
Given the pattern
computing the differences of all the adjacent terms
The difference between all the adjacent terms of the pattern is the same which is
Hence, the given pattern represents the Arithmetic sequence.
Therefore, the constant in the algebraic expression to represent the pattern below is 4.