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3 years ago

Please help aaa

Mathematics

2 answers:

Setler79 [48]3 years ago

7 0

Answer:

13/14

Step-by-step explanation:

13/35 is the probability of drawing 2 red candies.

2/5 = 14/35 is the probability of drawing 1 red candy.

13 and 14 make 13/14.

Hope This Helps :)

timofeeve [1]3 years ago

5 0

Drawing 2 red candies without replacement is 13/35.

Probability of picking one is 2/5.

We can say that the probability of the first candy being red is 2/5

So the probability of the second candy also being red would be 13/35 divided by 2/5 which = 13/14.

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natita [175]

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3 years ago

Jessica and Martha each have a bag of cookies with unequal quantities. They have 30 cookies total between the two of them. Each

Basile [38]

Answer:

Part 1) The inequality that describes the relationship between the number of cookies each one of them has is $x^{2} -30x+224\geq 0$

Part 2) Jessica has at least 2 cookies more than Martha

Step-by-step explanation:

Part 1) Find the inequality that describes the relationship between the number of cookies each one of them has

Let

x----> the number of cookies when Jessica started

30-x ----> the number of cookies when Martha started

we know that

Each of them ate 6 cookies from their bag

The cookies left in each bag are

(x-6) ----> Jessica

and (30-x-6)=(24-x) ---> Martha

The product is equal to (x-6)(24-x)

The product of the number of cookies left in each bag is not more than 80.

$(x-6)(24-x)\leq 80\\ \\24x-x^{2}-144+6x\leq 80\\ \\-x^{2} +30x-144-80\leq 0\\ \\-x^{2} +30x-224\leq 0$

Multiply by -1 both sides

$x^{2} -30x+224\geq 0$

Part 2) Solve the quadratic equation

$x^{2} -30x+224\geq 0$

Solve by graphing

The solution is x=16 cookies

(30-x)=30-16=14 cookies

therefore

The number of cookies when Jessica started was 16 cookies

The number of cookies when Martha started was 14 cookies

The number of cookies left in each bag is equal to

Jessica

16-6=10 cookies

Martha

14-6=8 cookies

Jessica has at least 2 cookies more than Martha

7 0

3 years ago

Read 2 more answers

List the sides in order from shortest to longest in ∆ABC, with m angle A = 80, m angleB = 3x + 5, and m angle C = 5x - 1.

galina1969 [7]

M<A + m5x - 1 = 180
8x + 84 = 180
8x =96
x = 12

m<B = 3x + 5 = 3(12) + 5 = 41
m<C = 5x - 1 = 5(12) - 1 =59
and
m<A = 80

answer:

order from shortest to longest in ∆ABC
AC, AB, BC

P.S.
Smallest angle, shortest side.....
Largest angle, longer side....

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wolverine [178]

Answer:

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Step-by-step explanation:

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