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zhenek [66]
3 years ago
11

Use the formula

Mathematics
1 answer:
natita [175]3 years ago
8 0
A=bh
108=<span>12*h
9in=h
The height is 9 inches.</span>
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What is -6(-3+5r)=-5-7r
inna [77]

Answer:

r = 1

Step-by-step explanation:

Use the distributive property to multiply −6 by −3+5r.

18−30r=−5−7r

Add 7r to both sides.

18−30r+7r=−5

Add −30r and 7r to get −23r.

18−23r=−5

Subtract 18 from both sides.

−23r=−5−18

Subtract 18 from −5 to get −23.

−23r=−23

Divide both sides by −23.

r=−23/−23​

Divide −23 by −23 to get 1.

r=1

8 0
3 years ago
What is a vector in linear algebra ?
Evgesh-ka [11]

Answer:

The definition of a vector that you learn in linear algebra tells you everything you need to know about what a vector is in any setting. A vector is simply an element of a vector space, period. ... So, to say that a vector is a column of numbers, or a geometric object with magnitude and direction, is incorrect

Step-by-step explanation:

i hope this helps at all

8 0
3 years ago
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The amount of eggs each of the fifteen preschool children gathered.
vladimir1956 [14]

Answer: yes

Step-by-step explanation:

5 0
3 years ago
Which equation describes the sum of the vectors plotted below?<br> -5
zalisa [80]

Answer:

Im not entirely sure but try B

6 0
4 years ago
Read 2 more answers
How am I supposed to figure this out if csc Theta(0) has a radical number on the top?
Harman [31]
\bf csc(\theta)=\cfrac{hypotenuse}{opposite}\implies csc(\theta)=\cfrac{\sqrt{7}}{2}\cfrac{\leftarrow hypotenuse=c}{\leftarrow opposite=b}\\\\&#10;-----------------------------\\\\&#10;\textit{so hmm using the pythagorean theorem, we can say that}\\\\&#10;c^2=a^2+b^2\implies \pm \sqrt{c^2-b^2}=a\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;b=opposite\\&#10;a=adjacent&#10;\end{cases}\\\\&#10;\textit{we'll assume is the + of the root, since you're not}\\&#10;\textit{given further info on it, that means the I quadrant}\\\\&#10;

\bf -----------------------------\\\\&#10;cos(\theta)=\cfrac{a}{c}\qquad sec(\theta)=\cfrac{c}{a}\qquad tan(\theta)=\cfrac{b}{a}\qquad cot(\theta)\cfrac{a}{b}&#10;

so just find the "adjacent" side, using the pythagorean theorem, and even though the square root can give you +/-, use the positive one, assuming the angle is in the 1st quadrant

keeping in mind, that the 2nd quadrant is feasible as well, since the opposite side of +2 can also be in the 2nd quadrant

but anyhow, use the I quadrant

7 0
3 years ago
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