Answer:
Part A. C=9
Part B. (w+3)² =139
Part C. w = 8.8 inch
Step-by-step explanation:
Given from the question length of the the picture = (2w+12) inches
Width of the picture = w inches
Area of the picture = 260 inch²
Part A. Area of the picture with the given dimensions= w×(2w+12)
Or w(2w+12) = 260
2w²+12w = 260
2(w²+6w) = 2×(130)
w²+6w = 130
Or w²+6w +9 = 130+9 ⇒ which is in the form of w²+6w+c = 130+c
Therefore for c = 9 we will get a perfect square trinomial.
Part B. As we have seen the equation in part A.
As required equation will be (w+3)²=139
Part C. Since (w+3)² = 139
Then by taking under root on both the sides of the equation
(w+3) =√139 = 11.8
(w+3)-3=11.8-3
w = 8.8 inch
Answer: B) x + y = 17
1.60x + 2.45y = 34
Step-by-step explanation:
Cost of x = $1.60 per pound
Cost of y = $2.45 per pound
Total pounds of x and y = 17
Cost per pound of mixture = $2
Total number of pounds of the mixture :
x + y = 17
Since the cost per pound of the mixture = 2
Hence ;
(Cost of x * number of pounds of x) + (Cost of y * number of pounds of y)
(1.60 * x) + (2.45 * y) = (cost per pound of mixture * total number of pounds of the mixture)
1.60x + 2.45y = 2 * 17
1.60x + 2.45y = 34
7900 should be the answer, is there any options?
Answer:
see below
Step-by-step explanation:
The angle where chords cross is the average of the intercepted arcs. Here, that is ...
(37° +46°)/2 = (83°)/2 = 41.5°
Angle SUT is 41.5°.
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<em>Comment on the error</em>
The measure of an arc cannot be arbitrarily said to be the same as the angle where the chords cross. It will be the same if (a) the chords cross at the circle center, or (b) the opposite intercepted arc has the same measure. Neither of these conditions hold here.
Answer:
And if we solve for a we got
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the hourly rates of a population, and for this case we know the distribution for X is given by:
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
Both conditions are equivalent on this case. We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.80 of the area on the left and 0.20 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.20
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got