Lizette ran for 1.25 hours and walked for 3 hours.
distance = speed × time
Her total distance is the sum of her distances at the different speeds. Let w represent her walking speed in mi/h. For distances in miles, speeds in miles per hour, and time in hours, the problem statement tells us ...
19 = (w+5)(1.25) + (w)(3)
19 = 4.25w + 6.25 . . . . collect terms
12.75 = 4.25w . . . . . . . subtract 6.25
3 = w . . . . . . . . . . . . . . . divide by 4.25
Lizette's walking speed is 3 mph.
Lizette's running speed is 8 mph.
I believe its 126 i hope that hepla
To find t? yes.
First, you combine like terms so 3t and 2t and 4t. Add 3 and 2 and then subtract the 4. you will end up with 1t (just t) +2. you cannot add the 2 because it does not have the variable t. on the other side, you will also combine like terms. so 3+5=8. now your equation is t+2=8. this is the part where you will try to get t by itself. subtract the 2 from the left side. but in order for the equation to stay equal to itself, you have to subtract 2 from the right side as well. this will leave you with your final answer of t=6.
