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3 years ago

Triangular a Recallyuldl

Mathematics

1 answer:

kramer3 years ago

5 0

i got 28cm.... But im not sure

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If ◻SLED ~ ◻PARK which of the following statements are incorrect?

san4es73 [151]

Answer:

◻DELS ~ ◻KARP is incorrect

Step-by-step explanation:

All of the similarity statements have corresponding letters in the same order except ...

◻DELS ~ ◻KARP . . . . (incorrect)

_____

The correct version would be ...

◻DELS ~ ◻KRAP

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2 years ago

Work out the size of angle EAB. <br> You must give a reason for each stage of your working.

Nadya [2.5K]

There’s no photo so we can’t help you sorry :(

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2 years ago

Select the expressions that are equivalent to 2(9r)

pashok25 [27]

Answer:

18r

Step-by-step explanation:

Multiply 9 by 2

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2 years ago

HELP PLEASE!!!!ASAP Giving out brainliest

QveST [7]

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2 years ago

A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

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2 years ago