Please solve both thank you!
2 answers:
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Answer:
D
Step-by-step explanation:
The equations are
● 4x + 2y = 10 (1)
● 4x - 2y = -10 (2)
● 4x + 2y = 10
Add - 4x to both sides
● 4x + 2y -4x = 10 -4x
● 2y = 10 -4x
Divide both sides by 2
● 2y/2 = (10 - 4x)/2
● y = 5 - 2x
● y = -2x + 5 (1)
● 4x - 2y = -10
Add -4x to both sides
● 4x -2y -4x = -10 - 4x
● -2y = -10 - 4x
Divide both sides by -2
● -2y/-2 = (-10 -4x)/-2
● y = 10 + 2x
● y = 2x + 5 (2)
So the equation are
● y = 2x + 5
● y = -2x + 5
Graph them
The lines intersect at (0,5) but aren't perpendicular
So the answer is d
We check with each options
'Or' represents the intersection of two graphs
'And' represents two separate graphs'
We have two separate shaded part in the given graph
So we ignore the options that has 'and' in between
LEts check first and second option
Simplify the first part and second part
multiply both sides by 2 .
x < 2 or 4x - 2 > = 26
solve 4x-2 > = 26
add 2 on both sides and then divide both sides by 4
4x >= 28
x >= 7
So solution is x<2 or x>=7 . that is the graph on number line
Lets check with second option
3x-3<3 or 2x+8>=22
add 3 on both sides
3x < 6
divide both sides by 3
so x< 2
2x+8>=22
subtract 8 on both sides
2x >= 30
divide both sides by 2
x >= 15
x<2 or x>=15 that does not satisfies the graph
So option A is correct