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3 years ago

Which of the following represents a function that is reflected over the x-axis and shifted up 3

Mathematics

1 answer:

Travka [436]3 years ago

7 0

Answer:

Option 2.

Step-by-step explanation:

f(x) = - x^2 + 3

The parent function is x^2

- the '-' before the x^2 reflects it in the x-axis, and the + 3 shifts it up 3 units.

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Alma got to the playground at 2:45.she spent 20 minutes on the swings and 10 minutes on the jungle gym. She played on the slide

Archy [21]

Answer:

Alma got home at 3:27

Step-by-step explanation:

2:45+30 min=3:15

3:15+12 min = 3:27

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3 years ago

Mini Sweets bake shop is running a special on cupcakes. For every 10 cupcakes purchased, 3 free cupcakes are added to the order.

Ierofanga [76]

She would get 9 free cupcakes

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3 years ago

SO<br> Determine the values of<br> a, b, and c for<br> the quadratic equation:<br> 4x2 - 8x = 3

Schach [20]

I believe it’s

a = 4
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3 years ago

The graph of f is given in the figure to the right. Let A(x)equals=Integral from 0 to x f left parenthesis t right parenthesis

Tpy6a [65]

Answer:

$A(4)=-4\pi$

$A(8)=-4\pi +8$

$A(12)=-4\pi +16$

$A(14)=-4\pi +15$

Step-by-step explanation:

we are given

$A(x)=\int\limits^x_0 f{x} \, dx$

Calculation of A(4):

we can plug x=4

$A(4)=\int\limits^4_0 f{x} \, dx$

Since, this curve is below x-axis

so, the value of integral must be negative

and it is quarter of circle

so, we can find area of quarter circle

radius =4

$A(4)=-\frac{1}{4}\times \pi \times (4)^2$

$A(4)=-4\pi$

Calculation of A(8):

we can plug x=8

$A(8)=\int\limits^8_0 f{x} \, dx$

we can break into two parts

$A(8)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx$

now, we can find area and then combine them

$A(8)=-4\pi +\frac{1}{2}\times 4\times 4$

$A(8)=-4\pi +8$

Calculation of A(12):

we can plug x=12

$A(12)=\int\limits^12_0 f{x} \, dx$

we can break into two parts

$A(12)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx$

now, we can find area and then combine them

$A(12)=-4\pi +\frac{1}{2}\times 8\times 4$

$A(12)=-4\pi +16$

Calculation of A(14):

we can plug x=14

$A(14)=\int\limits^14_0 f{x} \, dx$

we can break into two parts

$A(14)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx+\int\limits^14_12 f{x} \, dx$

now, we can find area and then combine them

$A(14)=-4\pi +\frac{1}{2}\times 8\times 4-\frac{1}{2}\times 1\times 2$

$A(14)=-4\pi +16-1$

$A(14)=-4\pi +15$

8 0

3 years ago

Factory by grouping 4x^3-8x^2+x-2

miss Akunina [59]

Answer:

(x-2) (4x^2+1)

Step-by-step explanation:

4x^3-8x^2+ x-2

Factor 4x^2 out of the first group and 1 out of the second group

4x^2 (x-2) +1(x-2)

Factor out (x-2)

(x-2) (4x^2+1)

7 0

3 years ago

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