All categories

2 years ago

Which of the following represents a function that is reflected over the x-axis and shifted up 3

Mathematics

1 answer:

Travka [436]2 years ago

7 0

Answer:

Option 2.

Step-by-step explanation:

f(x) = - x^2 + 3

The parent function is x^2

- the '-' before the x^2 reflects it in the x-axis, and the + 3 shifts it up 3 units.

You might be interested in

An angle is double its complement. find the angle and the complement

Alona [7]

Complement means the other angle that will sum up to 90°

So:

x + 2x = 90°
3x = 90
x = 30°

So, it is 30° and 30 * 2°, or 60°

4 0

2 years ago

Read 2 more answers

What expression shows the relationship between the value of any term and n, its position in the sequence for the given sequence?

san4es73 [151]

Answer:

a(n)=3+(n-1)2

Step-by-step explanation:

a(n)=3+(n-1)2

arithmetic sequence

5 0

2 years ago

What is 8,100 in scientific notation?

Rzqust [24]

8.1 I think but there's an app called, tiger something and it tells,you the answers

6 0

2 years ago

Find the surface area if the regular pyramid

lidiya [134]

9.1 yards because it’s just the answer because i know it’s the answer

4 0

1 year ago

A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long

Pie

Answer:

Surface area of pyramid with base equilateral triangle is $390+100\sqrt{3}$ square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

$S = \frac{1}{2}pl+B$ ...... (1)

Here, p represents the perimeter of the base , $l$ the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid( $l$ ) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = $3 \times (side)$

= $3 \times 20 = 60 inches$

Area of equilateral triangle(B) = $\frac{\sqrt{3} }{4} \times (side)^{2}$

= $\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}$ square inches.

Substitute the above values in equation (1) as shown below:

$S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}$

$S= 390+100\sqrt{3}$ square inches

Hence, the surface area of pyramid with base equilateral triangle is $390+100\sqrt{3}$ square inches.

6 0

2 years ago