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2 years ago

A. Find the slope of the line that passes through the points (2,-5) and (-2,3).

Mathematics

1 answer:

r-ruslan [8.4K]2 years ago

8 0

PART A:

Solve for the slope by solving change in y over change in x. We have (3-(-5)/(-2-2) = 8/-4=-2

PART B:

Change in to y=mx+b: -5y = -2x-10. Divide all terms by -5: y = 2/5x + 2. The slope is 2/5 and the y-intercept is 2.

PART C:

Remembering from part a that m=change in y/change in x, we have the equation: -4=1-(-9)/0-x. If we simplify, we have -4=10/0-x. If we multiply both sides from 1/10 we have: -2/5 = -x. So, x = 2/5.

PART D:

We can use point-slope form first:

y-5=-7(x+1). Then we solve the equation! y-5 = -7x-7. After adding 5 to both sides, we have the equation: y=-7x-2.

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Answer:

The area of the associated sector is $\frac{25}{24}\pi \ in^{2}$

Step-by-step explanation:

step 1

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we know that

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step 2

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we know that

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step 3

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we know that

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3 years ago

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We will now use the formula

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3 years ago

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3 years ago

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Answer:

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