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Alecsey [184]
3 years ago
11

1

Mathematics
1 answer:
UNO [17]3 years ago
7 0

Answer:

I think AAAAAAAAAAAAAAA

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Help pls with math lotsss of points!!!
sveticcg [70]

Answer:

5x^2+22x-12         x cannot be -5, -4, -2

(x+5)(x+4)(x+2)

Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)

Now that you have factored out the two quadratics, plug them into the equation.

    5x        -       3

(x+4)(x+2)      (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5)             -           3(x+4)  

(x+5)(x+4)(x+2)      (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

5x^2+25x - (3x+12)     =    5x^2+22x-12         x cannot be -5, -4, -2

 (x+5)(x+4)(x+2)               (x+5)(x+4)(x+2)

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Round to the nearest whole number. Simplify (5(12 - 2)2 + 7]/3=
mario62 [17]

(5(12-2)2+7)/3

(5(10)2+7)/3

(50(2)+7)/3

(100+7)/3

107/3

35.66666...

<h2><em>36</em></h2>
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