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Gala2k [10]
3 years ago
11

-8 and 8 are ___; they are both 8 away from zero.

Mathematics
1 answer:
Archy [21]3 years ago
4 0

Two numbers that are the same distance from zero are called opposites.

-8 and 8 are Opposites.

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Determine if -8T- 20 = 4(-2T -5) has one solution, infinitely many solutions, or no solution
AnnZ [28]

Answer:

infinitely many solutions

Step-by-step explanation:

-8T- 20 = 4(-2T -5)

Distribute the 4

-8T- 20 = (-8T -20)

Add 8T to each side

-8T+8T- 20 = (-8T+8T -20)

-20 = -20

Since this is a true statement, there are infinitely many solutions

8 0
3 years ago
Read 2 more answers
Evaluate the surface integral. s x ds, s is the part of the plane 18x + 9y + z = 18 that lies in the first octant.
IceJOKER [234]
In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.

(x,0,0)\implies 18x+9\cdot0+0=18\implies x=1
(0,y,0)\implies 18\cdot0+9y+0=18\implies y=2
(0,0,z)\implies 18\cdot0+9\cdot0+z=18\implies z=18

Now that we know the vertices of the surface \mathcal S, we can parameterize it by

\mathbf s(u,v)=\langle(1-u)(1-v),2u(1-v),18v\rangle

where 0\le u\le1 and 0\le v\le1. The surface element is

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=2\sqrt{406}(1-v)\,\mathrm du\,\mathrm dv

With respect to our parameterization, we have x(u,v)=(1-u)(1-v), so the surface integral is

\displaystyle\iint_{\mathcal S}x\,\mathrm dS=2\sqrt{406}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-u)(1-v)^2\,\mathrm dv\,\mathrm du=\frac{\sqrt{406}}3
5 0
3 years ago
Help 6,000 ÷ 20 - 34 × 8 + 12 ×9​
Strike441 [17]
The answer to your question is 136, pretty self explanatory
5 0
3 years ago
Assume that you take a both you fill a tub the halfway point the tub measures 5 feet long 2.1 gallons per minute. There are 7.5
MatroZZZ [7]

Answer:

both? use water for both of them

Step-by-step explanation:

8 0
3 years ago
Mabel is comparing the prices of two car rental companies. Company A charges $35 per day and an additional $15 as service charge
GalinKa [24]

Answer:

Part A:

<u>Equation for Company A: </u>

<u>x = Number of days renting a car</u>

<u>35x + 15</u>

<u>Equation for Company B:</u>

<u>x = Number of days renting a car</u>

<u>42x + 10</u>

Part B:

<u>Company A will charge $ 37 less than Company B</u>

Part C:

<u>Company A will charge $ 65 less than Company B</u>

Step-by-step explanation:

Part A:

Equation for Company A:

x = Number of days renting a car

35x + 15

Equation for Company B:

x = Number of days renting a car

42x + 10

Part B:

Renting a car for 6 days

Company A:

35 * 6 + 15 = 210 + 15 = $ 225

Company B:

42 * 6 + 10 = 252 + 10 = $ 262

Company A will charge $ 37 less than Company B

Part C:

Renting a car for 10 days

Company A:

35 * 10 + 15 = 350 + 15 = $ 365

Company B:

42 * 10 + 10 = 420 + 10 = $ 430

Company A will charge $ 65 less than Company B

4 0
3 years ago
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