<h3>G I V E N :</h3>
find the cost of the painting of a rectangular box of length 6m breadth 4m and height 3m at the rate of rs.25 per meter square
<h3>S O L U T I O N :</h3>
According to the question, first we need to get the T.S.A. or Total Surface Area of the cuboid then dividing it by ₹ 0.25 we can get the cost. After solving the concept will be more clear.
Let's start :
Here,
l represents length
b represents breadth
h represents height
Now, putting the values of all these we get
- T.S.A. = 2(6 × 4 + 4 × 3 + 3 × 6)
- T.S.A. = 2(24 + 12 + 18) m²
Now, we are given that cost of every square metre costs ₹ 0.25
So, for 108 m² it will cost = ₹ 108 × 0.25 = ₹ 27
<u>Hence, cost of painting the </u><u>rectang</u><u>ular box is ₹ 27</u>
Answer:
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Step-by-step explanation:
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8 9 10 11 12 13 14 (number of hours spent)
dot plot
$140 ÷ 18 = $7.7777
rounded = $7.78 per square foot
NOT SURE WHAT YOUR QUESTION WAS EXACTLY SO GAVE YOU SOME OPTIONS
or $140 for 18ft² = $140 for 324ft
or $140 ÷ 324ft = $0.43 per foot