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antiseptic1488 [7]

3 years ago

9

The students in Class A and Class B were asked how many pets they each have. The dot plots below show the results. What is the d

ifference between the ranges in the dot plots?

2 answers:

Mnenie [13.5K]3 years ago

7 0

Answer:

2

Step-by-step explanation:

The range of class A is 5-0 = 5

The range of class B is 3-0 = 3

the difference between 3 and 5 is 2.

irina [24]3 years ago

6 0

The mean can be calculated by adding all of the values and dividing that sum by the number of values you added. To take advantage of the way data is being collected, I am grouping the addends as, for example, 5(1), instead of writing out 1 + 1 + 1 + 1 + 1.

\A CLASS mean is:

B CLASS mean is:

Based on these findings, we can conclude that the mean for Mrs. Ramos' class is about 2 more than the mean for Mr. McIntyre's class.

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PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all

Xelga [282]

Answer:

1. $(A,B) = (3,-2)$

2. The values of t are: -3, -1

Step-by-step explanation:

Given

$\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

$|t| = 2t + 3$

Required

Solve for the unknown

Solving $\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

Take LCM

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}$

Expand the denominator

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}$

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}$

Both denominators are equal; So, they can cancel out

$x + 7 = A(x+1) + B(x-2)$

Expand the expression on the right hand side

$x + 7 = Ax + A + Bx - 2B$

Collect and Group Like Terms

$x + 7 = (Ax + Bx) + (A - 2B)$

$x + 7 = (A + B)x + (A - 2B)$

By Direct comparison of the left hand side with the right hand side

$(A + B)x = x$

$A - 2B = 7$

Divide both sides by x in $(A + B)x = x$

$A + B = 1$

Make A the subject of formula

$A = 1 - B$

Substitute 1 - B for A in $A - 2B = 7$

$1 - B - 2B = 7$

$1 - 3B = 7$

Subtract 1 from both sides

$1 - 1 - 3B = 7 - 1$

$-3B = 6$

Divide both sides by -3

$B = -2$

Substitute -2 for B in $A = 1 - B$

$A = 1 - (-2)$

$A = 1 + 2$

$A = 3$

Hence;

$(A,B) = (3,-2)$

Solving $|t| = 2t + 3$

Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

$t = 2t + 3$ and $-t = 2t + 3$

Solving $t = 2t + 3$

Make t the subject of formula

$t - 2t = 3$

$-t = 3$

Multiply both sides by -1

$t = -3$

Solving $-t = 2t + 3$

Make t the subject of formula

$-t - 2t = 3$

$-3t = 3$

Divide both sides by -3

$t = -1$

<em>Hence, the values of t are: -3, -1</em>

7 0

3 years ago

Read 2 more answers

What makes the sentence true 1\2=?/12

bagirrra123 [75]

It would be 1/2 = 6/12

6 0

3 years ago

Hannah's mom gave her a bag of chips she gives 6 chips to each other 10 friends she has 12 pieces left for herself how many kids

shutvik [7]

Answer:

72 chips

Step-by-step explanation:

6×10=60

60+12=72

7 0

3 years ago

Sally works at a store.

Ilya [14]

Answer:

Y is greater than or equal to 1/2x + 20

Y is less than or equal to 2/3x + 80

X is greater than or equal to 1200

X is less than or equal to 1850

Step-by-step explanation:

trust

8 0

3 years ago

Which of the following is the conjugate of 10 – 3i?

ipn [44]

we know that

The conjugate of a complex number is the number with equal real part and imaginary part equal in magnitude but opposite in sign

so

In this problem we have

$10-3i$

the conjugate is equal to--------> $10+3i$

therefore

<u>the answer is the option</u>

10+3i

3 0

3 years ago

Read 2 more answers