Answers 729 900 1,000
This is asking "how many numbers are there from 0 to 999 ? " :)
(remember to include 0)
They want all the passwords from 000 through 999 So that's 10 choices for each of the three places. 10^3 = 1000. :) or just list them all 000 001 002 003 ... 997 998 999 Which is 1,000 total codes.
Answer:
The decimal in simplest form is .625, and the fraction in simplest form is 5/8.
Step-by-step explanation:
To find the decimal that represents the shaded area, you have to find the fraction 5/8 and divide 5 by 8
Hope this helps!
Answer:
f(-2) = -3
Explanation:
Not sure if those last couple numbers are answer choices, but I'm going to infer that they might be.
Twenty four over the quantity of 3 x minus two in standard form is:
f(x) = <span>24<span>3x−2</span></span>
Since the number in the ( ) = x, plug in for x using f(-2)
<span>24<span>3∗<span>(−2)</span>−2</span></span>
P E {M D} {A S} for where to solve first
Multiply the 3 and (-2):
<span>24<span>−6−2</span></span>
Add -6 and -2:
<span>24<span>−8</span></span>
Divide the rest:
f(-2) = -3
Answer:
Number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.
Step-by-step explanation:
We are given that one wants to estimate the mean PSLT for the population of all families in New York City with gross incomes in the range $35.000 to $40.000.
If sigma equals 2.0, we have to find that how many families should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5.
Here, we will use the concept of Margin of error as the statement "true mean PSLT within 0.5" represents the margin of error we want.
<u></u>
<u>SO, Margin of error formula is given by;</u>
Margin of error =
where,
= significance level = 10%
= standard deviation = 2.0
n = number of families
Now, in the z table the critical value of x at 5% (
) level of significance is 1.645.
SO, Margin of error =
0.5 =
![\sqrt{n} =6.58](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D6.58)
n =
= 43.3 ≈ 43
Therefore, number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.