This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
All you have to do is just bring the numbers that are not zero from each digit.
so in this process, the answer you would get is 724,562.
I hope this helped
Answer:
48 pieces
Step-by-step explanation:
20÷5/12=20*12/5=240/5=48
Answer:it B I think
Step-by-step explanation:
I’m not sure though.
Y = (-1/9).x + 4
The slope m of the line perpendicular to y = (-1/9).x + 4 is equal to 9:
(if the product of 2 slopes = - 1, then the 2 lines are perpendicular)
y = 9x + b, Since it passes by the point (-1,0) , then:
0= 9(-1) + b and b = 9
Final equation:
y = 9x+9
