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dem82 [27]
3 years ago
7

I've already posted this once, and haven't got an answer, so I am posting it again just in case my question got lost in the sea

of other questions. I'd be really grateful if I got any help.

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0
I know the answer to 17 is the measure of each angle is 45° but i’m not sure about the rest sorry
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Please Solve this, it would be extremely helpful for me.
Sidana [21]

Answer:

Step-by-step explanation:

1) ΔCPD & ΔEPF

∠CPD = ∠EPF   { Vertically opposite angles}

∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}

ΔCPD ≈ΔEPF  {AA criteria for similarity }

\frac{DC}{EF} =\frac{PC}{EP}\\\\\\\frac{27}{EF}=\frac{15}{7.5}\\\\

Cross multiply

EF * 15 = 27 * 7.5

EF =\frac{27*7.5}{15}\\\\

EF = 27 * 0.5

EF = 13.5 cm

ii) EF // AB, so Triangles ACB & ECF are similar triangles

\frac{AB}{EF}=\frac{AC}{EC}\\\\\frac{22.5}{13.5}=\frac{AC}{22.5}

AC= \frac{22.5*22.5}{13.5}\\\\AC=37.5 cm

AC = 37.5 cm

6 0
3 years ago
!ASAP 10 points!!!<br> What is the value of y?
Rashid [163]

Answer:

a

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A 20 ft flag pole casts a shadow 32 ft long. What is the angle of elevation of the sun?
Nookie1986 [14]

Answer:

<em>The angle of elevation of the sun is 32°</em>

Step-by-step explanation:

<u>Right Triangles</u>

The flagpole and the ground form a right angle (90°). In triangles with right angles, the trigonometric ratios are satisfied.

Each acute angle has an adjacent leg and an opposite leg. The tangent ratio relates to both legs.

\displaystyle \tan x=\frac{\text{opposite leg}}{\text{adjacent leg}}

The opposite leg to angle x is 20 ft and the adjacent leg is 32 ft, thus:

\displaystyle \tan x=\frac{20}{32}=0.625

Calculate x by using the inverse tangent:

x=\arctan 0.625

x=32^\circ

The angle of elevation of the sun is 32°

7 0
3 years ago
Jacki evaluated the expression below.
Maru [420]

Answer: Jacki did not subtract 12 from 8 correctly

Step-by-step explanation: it should be -4

5 0
2 years ago
Read 2 more answers
Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among
Olegator [25]

Answer:

a) X[bar]₁=  1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

a)

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

b)

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

c)

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= \frac{1}{n_1-1}[∑X₁² - (( ∑X₁)²/n₁)]= \frac{1}{14} + [52829538 - (\frac{27588^{2} }{15}) = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0
3 years ago
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