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Varvara68 [4.7K]
3 years ago
11

How do you find arc ab

Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0
Use trigonometry to find the angle between the segments 3 and 6.
  ∠XOB = arccos(3/6) = 60°

The measure of arc AB is double that angle, since the figure is symmetrical about the line containing the segment of length 3.

m(arc AB) = 2·60° = 120°
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Answer:

g(-4) = -1

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If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.

As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.

It is a coincidence that g(-1) = -1.

Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.

We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3

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3 years ago
Someone please help! I'm confused with c and d.
Karo-lina-s [1.5K]

It would be 3 times the sum of x and seven plus 10. This is because first you would would add 7+x (7x) and multiply it by 3. And then add on 10.

5 0
3 years ago
Read 2 more answers
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