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polet [3.4K]
3 years ago
8

Does anyone know the answer??

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0
<6 = 38 (vertical angles)
---------------------

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A density curve for all the possible ages between 0 years and 100 years is in the shape of a triangle. What is the height of the
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<span>A density curve for all the possible ages between 0 years and 100 years is in the shape of a triangle. What is the height of the triangle?

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WHOEVER ANSWERS FIRST GETS BRAINLIEST AND I NEED AN EXPLANATION PLZ
Kruka [31]

Answer:

1.25b

Step by step explanation:

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The area of the parallelogram shown is (35x2 + 46x +15) square meters. If its base is (5x + 3) meters, find
attashe74 [19]

Answer:

(7x + 5)m

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
3 years ago
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