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cricket20 [7]
3 years ago
8

1,119.85 is estimate to what number

Mathematics
1 answer:
natita [175]3 years ago
7 0
1,120 is the estimate
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A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores
allochka39001 [22]

Answer:

Confidence interval = (4.61972, 25.46428)

Margin of Error = 3.9078675

Step-by-step explanation:

Given that :

This year:

Mean (μ1) = 64

Standard deviation (s1) = 13.8

Sample size (n1) = 28

Last year:

Mean (μ2) = 48.958

Standard deviation (s2) = 15.4

Sample size (n2) = 28

99% confidence interval estimate of the difference μ1−μ2

α = 1 - 99% = 0.01

(μ1−μ2) ± t0.01,27 * (√s1²/n1 + s2²/n2)

t0.01, 27 = 2.770683 (t value calculator)

√s1²/n1 + s2²/n2 = √13.8^2/28 + 15.4^2/28 = 3.9078675

(64 - 48.958) ± 2.667(3.9078675)

15.042 ± 10.42228

(15.042 - 10.42228), (15.042 + 10.42228)

(4.61972, 25.46428)

The margin of error :

√(s1²/n1) + (s2²/n2)

√(13.8^2/28) + (15.4^2/28)

√(6.8014285 + 8.47)

√15.2714285

= 3.9078675

3 0
3 years ago
A public library is currently open from 9am and 5pm on Saturday's. The director is considering whether or not to keep the librar
Lelechka [254]

Answer:

Yes i would use it between that time

Step-by-step explanation:

3 0
3 years ago
Please help, performance task: trigonometric identities
solong [7]

The answers are given below:

<h3>What is Trigonometry?</h3>

Trigonometry is a branch of mathematics that studies relationships between the sides and angles of triangles.

1. (cos x. cos y)(tan x + tan y) = sin (x+ y)

  (cos x. cos y)(tan x + tan y)

= cos x. cos y (sinx/ cos x + sin y/ cos y)

= sin x cos y + sin y cos x

= sin (x+ y)    [ sin ( x +y)]= sin x cos y + sin y cos x

= RHS

3. -\sin ^2\left(x\right)-\cos \left(2x\right)=0

Using identity

-\cos ^2\left(x\right)=0

cos ² x=0

Applying x^{n} =0 then x=0

So, cos x =0

General solution will be x=\frac{\pi }{2}+2\pi n,\:x=\frac{3\pi }{2}+2\pi n.

Learn more about trigonometry here:

brainly.com/question/12537661

#SPJ1

3 0
2 years ago
I NEED HELP 11POINTS
baherus [9]

Answer:

500=2.5x+200

x=the amount of desserts.

500-200=2.5x

300=2.5x

x=120

Step-by-step explanation:

8 0
3 years ago
In spring 2014, faculty from the City University of New York (CUNY) reported on a randomized controlled trial they conducted. Th
Tems11 [23]

Answer:

Explanatory variable: Extra support by faculties

Response variable: whether community college students who have assess into elementary algebra could be successful if they were placed directly into college-level statistics.

Confounding Variable: Ability of students to get passing grades.

It is an experiment to check if the hypothesis is true.

Step-by-step explanation:

An explanatory variable is a type of independent variable. An explanatory variable is that variable that explains changes in another variable. It can be anything that might affect the response variable. The explanatory variable is used to predict or explain differences in the response variable. In an experimental or research study, the explanatory variable is the variable that is manipulated by the researcher.

From the information given,

Explanatory variable: Extra support by faculties.

The response variable is also known as the dependent/outcome variable. Here, its value can be predicted or its variation can be explained by the explanatory variable. In an experimental study, this is the outcome that is measured after manipulation of the explanatory variable

From the question above,

Response variable: whether community college students who have assess into elementary algebra could be successful if they were placed directly into college-level statistics.

A confounding variable is that outside influence that changes the effect of a dependent and independent variable. This extraneous influence is often used to influence the outcome of an experimental design. The Confounding Variable in the above is:

Confounding Variable: Ability of students to get passing grades.

It is an experiment to check if the hypothesis is true.

6 0
3 years ago
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