There isnt one its has to be consistent but honestly idk
C. (x + 2)(x + 1)
it can be turned into an equation :)
Answer:
18.6 months
Step-by-step explanation:
Given that :
Best fit line from scatterplot :
y=-12.05x +224.26
x = Number of month
y = charge on battery
Number of months a typical battery uses before being dead completely :
When battery is dead completely ; charge =0, y = 0
y = -12.05x + 224.26
0 = - 12.05x + 224.26
12.05x = 224.26
x = 224.26 / 12.05
x = 18.610788
Hence, 18.6 months before battery is completely dead.
Answer:
(a)
and 
(b) The sample variance is
and the sample standard deviation is 
Step-by-step explanation:
(a)
The sum of these 17 sample observations is

and the sum of their squares is

(b)
The sample variance, denoted by
, is given by

where 
Applying the above formula we get that


The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

Applying the above formula we get that
