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3 years ago

50 POINTS LEASE HELPPP!!!!

Mathematics

1 answer:

xxMikexx [17]3 years ago

7 0

A regular octagon can be thought of as being composed of 4 "kite" shaped areas.

The area of a "kite" with diagonals d and w is

AreaKITE=d⋅w2.

(This is fairly easy to prove if it isn't a formula you already know).

Consider the "kite" PQCW in the diagram above.

∠QCW=π2 and |QC|=|WC|=r

s⇒|QW|=√2r (Pythagorean)

Therefore (since |PC|=r)

AreaPQCW=|PC|⋅|QW|2=r⋅√2r2=√2r^22

The octagon is composed of 4 such kites, so

AreaOctagon=2√2r^2

AreaOctogon=2√2(6)^2=101.823376491

AreaOctagon=101.8 units squared

here is the diagram https://d2gne97vdumgn3.cloudfront.net/api/file/80fl6nYTCaa5q8AZOyq0

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aleksandr82 [10.1K]

-1., 1, 2, 2

Step-by-step explanation:

A term is a single mathematical expression. It may be a single number (positive or negative), a single variable ( a letter ), several variables multiplied but never added or subtracted. Some terms contain variables with a number in front of them.

7 0

2 years ago

What is the value of s and the length of side BC if ABCD is a rhombus?

Natali5045456 [20]

Step 1

Find the value of s

we know that

In a Rhombus all sides are congruent

$AB=BC=CD=DA$

$AB=9s+29\\CD=10s-16$

equate AB and CD

$9s+29=10s-16\\$

Combine like term

$10s-9s=29+16\\$

$s=45\ units$

The answer Part a) is

the value of s is $45\ units$

Step 2

Find the value of side AB

$AB=9s+29$

substitute the value of s

$AB=9*45+29=434\ units$

Remember that the sides are congruent

$AB=BC=CD=DA$

therefore

the answer Part b) is

The length of the side BC is $434\ units$

4 0

3 years ago

Read 2 more answers

Please help with this question

12345 [234]

A^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = c^2
25 = c^2
5 = c

5 0

2 years ago

What are the domain, range, and asymptote of h(x) = (0.5)x – 9?

Rzqust [24]

Let's solve for h

hx = 0.5x - 9

Step 1: Divide both sides by x.

hx/x = 0.5x - 9/ x

Answer = h = 0.5x - 9/ x

8 0

2 years ago

Which expression is equivalent to 4(x^3)(2x)^-4

AVprozaik [17]

Answer:

= $\frac{4x^{3}}{16 x^{4}}$

Step-by-step explanation:

$4(x^{3} )(2x)^{-4}$

= $\frac{4x^{3}}{(2x)^{4}}$

= $\frac{4x^{3}}{2^{4} x^{4}}$

= $\frac{4x^{3}}{16 x^{4}}$

3 0

3 years ago