All categories

4 years ago

50 POINTS LEASE HELPPP!!!!

Mathematics

1 answer:

xxMikexx [17]4 years ago

7 0

A regular octagon can be thought of as being composed of 4 "kite" shaped areas.

The area of a "kite" with diagonals d and w is

AreaKITE=d⋅w2.

(This is fairly easy to prove if it isn't a formula you already know).

Consider the "kite" PQCW in the diagram above.

∠QCW=π2 and |QC|=|WC|=r

s⇒|QW|=√2r (Pythagorean)

Therefore (since |PC|=r)

AreaPQCW=|PC|⋅|QW|2=r⋅√2r2=√2r^22

The octagon is composed of 4 such kites, so

AreaOctagon=2√2r^2

AreaOctogon=2√2(6)^2=101.823376491

AreaOctagon=101.8 units squared

here is the diagram https://d2gne97vdumgn3.cloudfront.net/api/file/80fl6nYTCaa5q8AZOyq0

You might be interested in

If you can buy 1/2 of a gallon of milk for 3 dollars, how many gallons can you buy for 5 dollars? Write your answer as a fractio

maksim [4K]

Hey there!

1 gallon of milk = $6

The correct answer would be 3 1/2 gallons of milk or 3.5 gallons

6 0

4 years ago

Deandre is using the expression 3b + 4 to represent the number of cars in the mall parking lot. There are three times as many ca

never [62]

The number of parking spots

5 0

4 years ago

Read 2 more answers

Can someone help me please!!! Thank you

Semmy [17]

Steps of construction:

1. Draw a circle with centre B.

2. Draw a circle with centre C.

3. Both circles intersect each other at a point D

4. Join A and D.

5. So, AD bisects angle CAB.

A rough figure is shown in the picture.

5 0

3 years ago

Graph a parabola whose intercepts are x=-3 and x=5 and whose minimum value is y =-4

blagie [28]

Answer:

$y = 4(x^{2} + 8x + 15) = 4x^{2} + 32x + 60$

Step-by-step explanation:

A parabola has the following format:

$y = f(x) = ax^{2} + bx + c$

If a is positive, it's minium value is:

$y_{M} = -\frac{\bigtriangleup}{4a}$

In which

$\bigtriangleup = b^{2} - 4ac$

Factoring:

$ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , in which $x_{1} and x_{2}$ are the intercepts.

In this question:

$x_{1} = -5, x_{2} = -3$

$a(x - x_{1})*(x - x_{2}) = a*(x - (-5))*(x - (-3)) = a*(x+5)*(x+3) = a*(x^{2} + 8x + 15)$

Suppose a = 1, we have:

$x^{2} + 8x + 15$

$\bigtriangleup = 8^{2} - 4*1*15 = 4$

The minimum value will be:

$y_{M} = -\frac{4}{4} = -1$

We want this minimum value to be -4, which is 4 times the current minimum value, so we need to multiply a by 4. Then

$a = 4$

And the parabola is:

$y = 4(x^{2} + 8x + 15) = 4x^{2} + 32x + 60$

4 0

3 years ago

Write the expression as a product of the to factors: 6m+ 8n+ 4

Whitepunk [10]

Answer:

No answer do u today

Step-by-step explanation:

Lol

H hi ha job un hi is ihnihniuniunihn como te quiero

8 0

3 years ago