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trapecia [35]
3 years ago
12

Compare 8.25 and 8.250

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0
The answer is = because of you take away the 0 in the decimal 8.250 it's the same decimal as 8.25 and in decimals the zeros farthest to the right don't matter.
8.25 = 8.250
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She could borrow $2500 at a monthly interest rate of 4% simple interest and pay the total after 12 months. Write a simple-intere
Harlamova29_29 [7]

Answer:

She would owe $3,700 at the end of 12 month.

Step-by-step explanation:

Simple interest formula:

I=Prt

I= Interest

P=principal

r= Rate of interest

t=time

Given that, she could borrow $2,500. So P=$2,500.

The rate 4%=0.04 per month and time t= 12 months.

The interest I = $(2,500×0.04×12)

                      =$1,200

Amount = principal+ Interest

             =$(2,500+1,200)

             =$3,700

She would owe $3,700 at the end of 12 month.

7 0
3 years ago
What’s the slope of (2,4) and (4,9)
serious [3.7K]

Answer:

2.5

Step-by-step explanation:

6 0
4 years ago
Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y
koban [17]

\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}

Substituting this into the other ODE gives

-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0

Since x(t)=-\dfrac14y'(t), it follows that x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16. The ODE in y has characteristic equation

r^2-16=0

with roots r=\pm4, admitting the characteristic solution

y_c=C_1e^{4t}+C_2e^{-4t}

From the initial conditions we get

y(0)=5\implies 5=C_1+C_2

y'(0)=16\implies-16=4C_1-4C_2

\implies C_1=\dfrac12,C_2=\dfrac92

So we have

\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}

Take the derivative and multiply it by -1/4 to get the solution for x(t):

-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}

7 0
4 years ago
The sum of three consecutive numbers is equal to 4 times the largest number minus 29. What is the smallest of the three numbers?
gulaghasi [49]

The smallest of the three consecutive integers is 24.

<h3>How to solve algebraic word problems?</h3>

Let the 3 consecutive integers be;

x, y and z

Thus;

y = x + 1

z = x + 2

Now, we are told that their sum is equal to 4 times the largest number minus 29. Thus;

x + x + 1 + x + 2 = 4(x + 2) - 29

3x + 3 = 4x + 8 - 29

4x - 3x = 3 + 21

x = 24

Thus, we can conclude that the smallest of the three consecutive integers is 24.

Read more about algebra word problems at; brainly.com/question/13818690

#SPJ1

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Answer:

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Step-by-step explanation:

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