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2 years ago

A baseball diamond has an area of 3,600 ft. square. What is the distance between each base.

Mathematics

2 answers:

snow_lady [41]2 years ago

4 0

Answer:

A diamond is the same thing as a square. So the side lengths are all the same. Multiplied length by width you get area. So square the area (3600) and you get 60 feet side length. The bases are 60 feet away from each other.

SLOVIN

A baseball diamond is just like a square, meaning the area of the baseball diamond can be calculate with: , where s = side, and A = area.

Plug in area value.

Take square root of both sides.

(since 6 x 6 = 36, then 60 x 60 = 3600)

the distance between each base is 60 feet.

goldfiish [28.3K]2 years ago

3 0

Answer:

60 feet

Step-by-step explanation:

1. A baseball diamond is just like a square, meaning the area of the baseball diamond can be calculate with: $s^2 = A$ , where s = side, and A = area.

2. (Solving)

Step 1: Plug in area value.

$s^2 = 3600$

Step 2: Take square root of both sides.

$\sqrt{s^2} = \sqrt{3600$
(since 6 x 6 = 36, then 60 x 60 = 3600)
$s = 60$

Therefore, the distance between each base is 60 feet.

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4 years ago

Read 2 more answers

Say a hacker has a list of n distinct password candidates, only one of which will successfully log her into a secure system. a.

alexdok [17]

Answer:

The probability is $\frac{1}{n}$

Step-by-step explanation:

If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:

If k=1

$P = \frac{1}{n}$

Because, in her first try she has n possibles options and just one give her a successful login.

If k=2

$P=\frac{n-1}{n} *\frac{1}{n-1} =\frac{1}{n}$

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.

If k=3

$P=\frac{n-1}{n} *\frac{n-2}{n-1} *\frac{1}{n-2} = \frac{1}{n}$

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.

Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n

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3 years ago

Does each function describe exponential growth or decay?

Aleksandr [31]

<h3>Answer: Only first two are exponential growth function and last three functions are exponential decay functions.</h3>

Step-by-step explanation: We need to describe exponential growth or decay for the given functions.

The standard exponential function equation is

$y=a(b)^x$ .

Where a is the initial value and b is the growth factor.

Note: If value of b > 1, it would be an exponential growth and if b < 1, it would be an exponential decay.

Let us check them one by one.

$y=(1.008^{1/12}})^{12t}$ => $y=(1.008^})^{1/12\times{12t} }$

=> $y= (1.008)^t$ .

Value of b is 1.008 > 1, therefor it's an exponential growth function.

y=250(1+0.004)^t, also have b>1 therefor it's an exponential growth function.

All other functions has b values less than 1, therefore only first two are exponential growth function and last three functions are exponential decay functions.