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sattari [20]
3 years ago
12

In a certain function, an output is 4 more than half its input.

Mathematics
1 answer:
patriot [66]3 years ago
7 0

Answer:

x          y

-10      -1

0         4

4          6

6          8

Step-by-step explanation:

an output is 4 more than half its input.

Input of a function is x and the output of a function is y

output y is 4 + half of input x

y= \frac{1}{2} x + 4

Now we complete the below table, plug in the value of x  and find out y

x = -10 , y= \frac{1}{2}(-10) + 4=-5+4 = -1

x = 0 , y= \frac{1}{2}(0) + 4=0+4 = 4

x = 4 , y= \frac{1}{2}(4) + 4=2+4 = 6

x = 8, y= \frac{1}{2}(8) + 4=4+4 = 8


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1/3 is the slope, or 1 over 3. 
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Adam found a bag of money that he split with 22 friends.
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Answer:

x/23

Step-by-step explanation:

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3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
The product of negative nine and x
Montano1993 [528]
<u>-9x
</u>........................................<u>
</u>
4 0
4 years ago
a trapezoid with base measure of 23 km and 29km an area of 390km . find the height of the trapezoid.
cupoosta [38]
Hello!

To find the area of a trapezoid you use the equation

A =  \frac{a+b}{2} h

Put in the values you know

390 =  \frac{23+29}{2} h

Add

390 = \frac{52}{2} h

Divide

390 = 26 * h

Divide both sides by 26

15 = h

The answer is 15km

Hope this helps!
3 0
4 years ago
Read 2 more answers
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