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Kay [80]
3 years ago
7

4) Get Fit Headquarters charges $40 per month and $3 per exercise class. Fit Planet

Mathematics
1 answer:
Allisa [31]3 years ago
6 0

Answer:

After 4 exercise classes, the monthly cost will be the same at each gym

The cost will be $52

Step-by-step explanation:

Assume that the number of the exercise classes is x

∵ Get Fit Headquarters charges $40 per month and $3 per exercise class

∵ The number of the exercise classes is x

→ Add $40 to the product of x and $3 to get the monthly cost

∴ The monthly cost of Get Fit = 3x + 40

∵ Fit Planet charges $20 per month and $8 per exercise class

∵ The number of the exercise classes is x

→ Add $20 to the product of x and $8 to get the monthly cost

∴ The monthly cost of Fit Planet = 8x + 20

∵ They have the same monthly cost

→ Equate their monthly cost to find x

∴ 8x + 20 = 3x + 40

→ Subtract 3x from both sides

∵ 8x - 3x + 20 = 3x - 3x + 40

∴ 5x + 20 = 40

→ Subtract 20 from both sides

∵ 5x + 20 - 20 = 40 - 20

∴ 5x = 20

→ Divide both sides by 5

∴ x = 4

∵ x is the number of the exercise classes

∴ After 4 exercise classes the monthly cost will be the same at each gym

→ Substitute the value of x in one of the monthly cost to get it

∵ The monthly cost of the Get Fit = 3(4) + 40

∴ The monthly cost of the Get Fit = 12  +40

∴ The monthly cost of the Get Fit = 52

∴ The cost will be $52

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WINSTONCH [101]

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.  

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Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}

Seperate the differential equation and solve for the constant C.

\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2}  }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}

You have 100 rodents when:

100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months

You have 1000 rodents when:

1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months

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2 years ago
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Answer: 20 i think srry if its wrong

Step-by-step explanation:

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densk [106]

Answer:

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Step-by-step explanation:

Given is a polynomial in x

F (x)= x^4 + 12x^3 + 30x^2 - 12x + 70

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Remainder theorem says that f(x) gives remainder R when divided by polynomial x-a means f(a) = R

Applying the above theorem we can say that value of the function when x =-5

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Substitute the value of -5 in place of x

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Answer:

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Therefore, -311 is our answer.

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