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deff fn [24]
3 years ago
6

If lengths of two sides of an isosceles triangle are 4 and 12, what is perimeter of the triangle?

Mathematics
1 answer:
damaskus [11]3 years ago
8 0
4 + 12 +12 = 28cm
  so in conclusion it is 28
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Please help me thank you.
Alexxandr [17]

Answer:

B

Step-by-step explanation:

3      -4    |   2

0      -1     |   7

3/2    -2    |   1

R1/3 ----> R1  (divide Row 1 by 3)

1       -4/3    |  2/3

0        -1      |   7

3/2      -2     |   1

R3 - 3/2  R1 -------> R3 (multiply Row 1 by 3/2 and subtract it from Row 3)

1      -4/3    |   2/3

0       -1      |    7

0       0      |    0

R2 / -1 -------> R2 (Divide Row 2 by -1)

1      -4/3   |  2/3

0        1     |   -7

0        0    |   0

R1 + 4/3 R2 --------> R1 (Multiply Row 2 by 4/3 and add it to Row 1)

1     0     |   -26/3

0    1      |      -7

0    0     |      0

5 0
3 years ago
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
3 years ago
Find the GCF of the given list.<br>x^17 y^3, x^4 y^3, x^5 y^5 ​
trasher [3.6K]

Answer:

the greatest common factor is 1.

Step-by-step explanation:

The factors of 3 are: 1, 3

The factors of 3 are: 1, 3

The factors of 4 are: 1, 2, 4

The factors of 5 are: 1, 5

The factors of 5 are: 1, 5

The factors of 17 are: 1, 17

Then the greatest common factor is 1.

7 0
2 years ago
What is the correct answer
krek1111 [17]

Answer:

3x - 9 - (6 / (x+4))

Step-by-step explanation:

               3x - 9

              |----------------------------------------

(x +4)       | (3x^2 + 3x - 42 )

                 3x^2 + 12x

           ------------------------------

                          -9x - 42

                          -9x - 36

-----------------------------------

                                 - 6

Answer: 3x - 9 - (6 / (x+4))

8 0
3 years ago
Read 2 more answers
How do you solve V+6V=59
trasher [3.6K]
Honestly, I don't know the answer but I am did the middle school and I believe it is 2V=9.83 repeating. The 3 is repeating
5 0
3 years ago
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