Answer:
There is 5720 J of heat released.
Explanation:
Step 1: Data given
Molar mass of CH6N2 = 46.07 g/mol
The heat of combustion of methylhydrazine is −1.30 × 103 kJ/mol
Mass of methylhydrazine = 202.7 grams
Step 2: Calculate number of moles
Moles CH6N2 = mass of CH6N2 / Molar mass CH6N2
Moles CH6N2 = 202.7 grams / 46.07 g/mol
Moles CH6N2 = 4.4 moles
Step 3: Calculate heat released when 202.7 grams of CH6N2 is burned
q = 1300 J/mol * 4.4 moles
q = 5720 J
(Since there is heat released, ΔH = negative)
There is 5720 J released.
Answer:
The answer to your question is 1 M
Explanation:
Data
Molarity = ?
mass of CaCl₂ = 222.2 g
Volume = 2 l
Process
1.- Calculate the molar mass of CaCl₂
CaCl₂ = 40 + (35.5 x 2) = 40 + 71 = 111 g
2.- Calculate the moles of CaCl₂
111g of CaCl₂ ---------------- 1 mol
222.2 f of CaCl₂ ---------------- x
x = (222.2 x 1) / 111
x = 222.2 / 111
x = 2 moles
3.- Calculate the Molarity
Molarity = moles / Volume
-Substitution
Molarity = 2/2
-Result
Molarity = 1
Answer:
It would have to be around 9.8 volume
Explanation:
They are <span>Common Soil </span><em>Bacteria</em><span> Nematodes.
Hope this helps:)</span>
