What is the volume of 2.00 moles of ideal gas at 25'c and 121.59 kpa of pressure
1 answer:
Answer:
40.73 L.
Explanation:
We can use the general law of ideal gas: <em>PV = nRT. </em> where, P is the pressure of the gas in atm (P = 121.59 kPa/101.325 = 1.2 atm) .
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 2.0 mol).
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas in K (T = 25°C + 273 = 298 K).
<em>∴ V = nRT/P </em> = (2.0 mol)(0.082 L.atm/mol.K)(298 K)/(1.2 atm) = <em>40.73 L. </em>
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