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3 years ago

What is the volume of 2.00 moles of ideal gas at 25'c and 121.59 kpa of pressure

Chemistry

1 answer:

katrin [286]3 years ago

6 0

Answer:

40.73 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 121.59 kPa/101.325 = 1.2 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 2.0 mol).

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K (T = 25°C + 273 = 298 K).

∴ V = nRT/P = (2.0 mol)(0.082 L.atm/mol.K)(298 K)/(1.2 atm) = 40.73 L.

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The C=C bond in 2-cyclohexenone produces an unusually strong signal. Explain using resonance structuresBased on the above resona

frosja888 [35]

Answer:

When two single single bonds separated by a double bond (e.g C=C-C=C or C=C-C=O in the case of 2-cyclohexenone), the effect of resonance among those there bonds will be observed.

Explanation:

Since the Oxygen atom has higher electronegativity, it will cause the electrons in the resonance bonds 'flow' toward the Oxygen atom, so that the C=C will 'lose' some electron. The signal read for that bond will be different from other alkene structure.

Attachment is the resonance structure of 2-cyclohexene.

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3 years ago

A species that is formed when a base gains conjugate base. b. conjugate acid. a proton is a c. strong base d. strong acid.

SSSSS [86.1K]

Answer:

The correct option is: conjugate acid

Explanation:

Bases are the chemical substances that are proton acceptors and electron-pair donors. Therefore, when a base accepts a hydrogen proton from an acid it forms a conjugate acid.

Therefore, conjugate acids are formed when a base accepts a hydrogen proton from an acid. Also, if the base is a weak base then its conjugate acid is strong. Whereas, if the base is a strong base then the conjugate acid is weak.

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3 years ago

Which one of the following is not equal to 100 meters?

julsineya [31]

10 hectometers

One hectometer is 100 meters in length already, so 10 is 1000

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3 years ago

A pool is 60.0 m long and 35.0 m wide. How many mL of water are needed to fill the pool to an average depth of 6.35 ft? Enter yo

ra1l [238]

Answer:

4.07 × 10⁹ mL

Explanation:

Step 1: Given data

Length of the pool (L): 60.0 m

Width of the pool (W): 35.0 m

Depth of water in the pool (D): 6.35 ft

Step 2: Convert "D" to m

We will use the relationship 1 m = 3.28 ft

$6.35ft \times \frac{1m}{3.28ft} = 1.94m$

Step 3: Calculate the volume of water (V)

We will use the following expression.

$V = L \times W \times D = 60.0m \times 35.0m \times 1.94 m = 4.07 \times 10^{3} m^{3}$

Step 4: Convert "V" to mL

We will use the relationship 1 m³ = 10⁶ mL.

$4.07 \times 10^{3} m^{3} \times \frac{10^{6}mL }{1m^{3} } = 4.07 \times 10^{9} mL$

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3 years ago

Why did Dalton think it was important to use his system of symbols for the chemical elements?

Dimas [21]

Explanation:

to remind people that atoms were

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4 years ago