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igomit [66]
3 years ago
14

The perimeter of a particliar rectangle is 24 inches.if the length and width are positive integers,how many disinct areas could

the rectangle have.
Mathematics
2 answers:
Vilka [71]3 years ago
5 0
Let's set one side a rectangle as x and the other distinct one as y.

The perimeter would be x+x+y+y=24, or 2x+2y=24. This can be simplified to x+y=12.

Since the area is xy, we just have to find how many combinations of positive integer numbers add up to 12.

1 and 11 (area of 11)
2 and 10 (area of 20)
3 and 9 (area of 27)
4 and 8 (area of 32)
5 and 7 (area of 35)
6 and 6 (area of 36)

That's it.

So, this rectangle could have 6 distinct areas.

Hope this helps!
just olya [345]3 years ago
4 0
6 distinct areas. hope this helps luv
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Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x, y =
miss Akunina [59]

Answer:

381.18 cubic units

Step-by-step explanation:

Graph the region:

desmos.com/calculator/iwvreqjz2m

The region is a trapezoid.  When we rotate it about x = 1, we get a hollow cylinder shape.  We can either use washer method or shell method to find the volume.

If we find the volume using washer method, we'll have to use two integrals, one for the triangular part of the trapezoid and one for rectangular part.  If we use shell method, we only need one integral.  So let's use shell method.

Cut a thin, vertical slice of the region.  The width of this slice is dx.  The height of the slice is y₂ − y₁ = x − 0 = x.  The radius of the shell is x − 1.

The volume of the shell is:

dV = 2π (x − 1) (x) dx

dV = 2π (x² − x) dx

The total volume is the sum of all the shells from x=5 to x=7.

V = ∫ dV

V = ∫₅⁷ 2π (x² − x) dx

V = 2π ∫₅⁷ (x² − x) dx

V = 2π (⅓ x³ − ½ x² + C) |₅⁷

V = 2π [(⅓ 7³ − ½ 7² + C) − (⅓ 5³ − ½ 5² + C)]

V = 2π [⅓ 7³ − ½ 7² − ⅓ 5³ + ½ 5²]

V = 2π [⅓ (7³ − 5³) + ½ (5² − 7²)]

V = 2π [⅓ (218) + ½ (-24)]

V = 2π (72⅔ − 12)

V = 121⅓ π

V ≈ 381.18

The volume is approximately 381.18 cubic units.

6 0
3 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
4 years ago
Chanel pays 7% sales tax on a boat that costs 5,600 dollars. How much does the sales tax add to the purchase price?
DerKrebs [107]

Answer:

329

Step-by-step explanation:

because i just did the assingment

3 0
3 years ago
if f(g(x)) = x and g(f(x)) = x, and f(x) passes through the point (5,-7), and g'(-7) = -2/3, then find the value of f'(5).
Marysya12 [62]
So it is given that f(x) and g(x) are inverse of each other.

Then f(5) = -7 and hence g(-7) = 5

Now let's use f( g( x ) ) = x

Now take deviation. Use chain rule:

f'( g(x) ) g'( x ) = 1

Plug in x = -7

f'( g( -7 ) ) g'( -7 ) = 1

f'( g( -7 ) ) · -2/3 = 1

f'( g( -7 ) ) = -3/2

f'( 5 ) = -3/2

Hope this helps.
5 0
3 years ago
I will mark you as brainliest please answer with way and dont send anything useless thing if you are not answering you can send
Delicious77 [7]

Answer:

24

Step-by-step explanation:

There are two triangles PQR, each with area base*half heigth = 6*2 = 12, and two times 12 is 24.

6 0
3 years ago
Read 2 more answers
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