Answer:

Step-by-step explanation:
Given:
Given point P(6, 6)
The equation of the line.

We need to find the equation of the line perpendicular to the given line that contains P
Solution:
The equation of the line.

Now, we compare the given equation by standard form 
So, slope of the line
, and
y-intercept 
We know that the slope of the perpendicular line 



So, the slope of the perpendicular line
From the above statement, line passes through the point P(6, 6).
Using slope intercept formula to know y-intercept.

Substitute point
and 




So, the y-intercept of the perpendicular line 
Using point slope formula.

Substitute
and
in above equation.

Therefore: the equation of the perpendicular line 
y = 3(x + 4)^2 + 31
Step-by-step explanation:
We can convert the given quadratic equation into its vertex form by completing the square:
y = 3x^2 + 24x + 43
= 3(x^2 + 8x) + 43
= 3(x^2 + 8x + 4) + 31
= 3(x + 4)^2 + 31
This is the vertex form of the given quadratic equation with (-4, 31) as its vertex
We can use the points (-6, 2) and (-4, 13) to solve.
Slope formula: y2-y1/x2-x1
= 13-2/-4-(-6)
= 11/2
______
Best Regards,
Wolfyy :)
49.26 because 90-40.74=49.26
Sorry but I can’t see the picture