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sattari [20]
2 years ago
8

Which strategy is the most appropriate strategy to solve 5x^2−x+3=0 ?

Mathematics
2 answers:
Liula [17]2 years ago
7 0
We are given with the quadratic equation <span>5x^2−x+3=0 and is asked in the problem the correct way to determine the values of the roots. we can answer this problem using the quadratic formula since in the first place this is a quadratic equation. C is the answer.</span>
goblinko [34]2 years ago
4 0

Answer:

Option C - The best strategy is quadratic formula.

Step-by-step explanation:

Given : Equation - 5x^2-x+3=0

To find : Which strategy is the most appropriate strategy to solve.

Solution :

The best strategy is quadratic formula as the given equation is in form of quadratic.

Quadratic equation is in from ax^2+bx+c=0

Solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

The given equation is 5x^2-x+3=0

a=5 , b=-1, c=3

Solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(5)(3)}}{2(5)}

x=\frac{1\pm\sqrt{1-60}}{10}

x=\frac{1\pm\sqrt{-59}}{10}

x=\frac{1\pm\sqrt{59}i}{10}

x=\frac{1+\sqrt{59}i}{10},x=\frac{1-\sqrt{59}i}{10}

Therefore, Option C - The best strategy is quadratic formula.

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Does anyone know the answer to this question?
miv72 [106K]

a) means what is the probability of P occurring once Q has occurred. That is 9/24 which is 3/8.

b) is 14/24 which is 7/12.

Please inform me if I gave you the correct answers :)

3 0
2 years ago
What is the answer please help
hram777 [196]

Answer:

B: 22.5 degrees

Step-by-step explanation:

The interior angles of a pentagon add up to 540 degrees

(if you dont believe me you can turn a pentagon into three triangles, 3x180 = 540)

So you have four same angles say measure "x" degrees, and one final one that measures "5x" degrees, so 9x = 540, and x = 60

Unless I read the problem wrong, 60 degrees is the answer which is not an option :P

Edit: Yea I read it wrong, the final angle is 5 times the other four angles COMBINED, so that angle measures "20x" degrees.

The total would be 24x = 540, and so x = 22.5

4 0
2 years ago
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
2 years ago
Whats the answer giving brainliest to the c o rect anwers
Flauer [41]

Answer:

A

Step-by-step explanation:

9/3 is 3

36-3 is 33

6 0
3 years ago
Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8
Lelu [443]
It depends on what did you mean by saying perfect square. If I've understood it correctly, I can help you with a part of your problem. The squares of mod <span>9</span><span> are </span><span><span>1</span><span>,4,7</span></span><span> which are came from </span><span><span>1,2,</span><span>4.</span></span><span> </span>Addition of the given numbers are 2,3,5,6, 8, which are exactly the part of your problem. This number, which is not shown as squares Mod 9, and thus doesn't appear as a sum of digits of a perfect square. I hope you will find it helpful.
5 0
2 years ago
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