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Scorpion4ik [409]
2 years ago
6

The slope of a line is -1/3 Find the slope of a line that is perpendicular to this line.

Mathematics
2 answers:
Kitty [74]2 years ago
3 0

Answer:

3

Step-by-step explanation:

To find the slope of a line perpendicular to a like with a gradient of -1/3, you do the negative reciprocal of -1/3 which would be 3/1 or 3.

iren [92.7K]2 years ago
3 0

Answer:

3

Step-by-step explanation:

let, m = -1/3

and, m1 = x

m * m1 = -1

m1 = -1/-1/3

m1 = 3......

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A rectangular table top measures 8/9 of a meter long by 2/3 of a meter wide. what is its area
erma4kov [3.2K]
Area= l×w
       = 8/9 × 2/3
       =16/27
     area = 16/27 m²
hope i hel[ped
6 0
3 years ago
Count by ones from 368 to 500. Change for a larger unit when necessary.
stepan [7]
We can figure out how many numbers there are from 368 to 500 by subtracting.

500 - 368 = 132

Now, we need to get it in word form. This can be done by looking at the place value of each number.. So your answer would be:

1 hundred, 3 tens, and 2 ones.
6 0
3 years ago
A 50 foot ladder is set against the side of a house so that it reaches up 30 feet. If
Allisa [31]

Answer:

21.8

Step-by-step explanation:

7 0
3 years ago
Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)
inysia [295]
If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 9 &,& 4~) 
%  (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}

\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 9 &,& 4~) 
%  (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}

\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45
7 0
3 years ago
Help?<br><br> a) 2/10 + 8/100<br> b) 13/100 + 4/10<br> c) 6/10 + 39/100<br> D) 70/100 + 3/10
Leni [432]

\green{––––––––––––––––––––––––––––––}

\huge\red{\boxed{\tt{{«ANSWER»}}}}

  • A) 2/10 + 8/100 = <u>0</u><u>.</u><u>2</u><u>8</u>
  • B) 13/100 + 4/10 = <u>0</u><u>.</u><u>5</u><u>3</u>
  • C) 6/10 + 39/100 = <u>0</u><u>.</u><u>9</u><u>9</u>
  • D) 70/100 + 3/10 = <u>1</u>

<u>\green{––––––––––––––––––––––––––––––}</u>

<em><u>#</u></em><em><u>carry </u></em><em><u>on </u></em><em><u>learning </u></em><u><</u><u>3</u>

5 0
2 years ago
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