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2 years ago

A line that includes the points (q,3) and ( - 6, - 2) has a slope of 5. what is the value of q?

Mathematics

1 answer:

yulyashka [42]2 years ago

8 0

5 = (-2-3)/(-6-q) = -5/(-6-q)
We divide both sides by -5 and obtain
-1 = -6 -q --> q= -5

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2 years ago

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RoseWind [281]

Answer:x=1.5

Step-by-step explanation:

Given

Two points co-ordinates are given

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B=(5,4)

let other point be C =(x,y)

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$A=\begin{vmatrix}5& -8&1\\5& 4&1\\x& y&1\end{vmatrix}$

$A=5\left ( 4-y\right )+8\left ( 5-x\right )+1\left ( 5y-4x\right )$

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2 years ago

The slope of the line whose equation is x + y = 6 is: -1 1 6

nadya68 [22]

Answer:

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2 years ago

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Step2247 [10]

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2 years ago

Read 2 more answers

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$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
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-------------------------------\\\\$

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\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
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2 years ago